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What part of the
#include<conio.h>
#include<stdio.h>
main()
{
(1) int no1,no2;
printf(“Input 1st Number: ”);
scanf(“%i”,&no1);
printf(“\nInput 2nd Number: ”);
(2) scanf(“%f”,&no2);
(3) printf(“\nThe First number is %i and the Second number is %i”,no1,no2);
getch();
return 0;
}
Step by step
Solved in 2 steps
- Given the code below: type point real a, b end type type (point) v read*, v z=v%a/v%b print*, z end What is the equivalent code for the above statements? Question 6 options: none of the given code choices type point real a, b end type type (point), dimension(2):: v read*, v do i=1, 2 z=v(i)%a/v(i)%b end do print*, z end all the given code choices type point real a, b end type type (point), dimension(2):: v read*, v where (i>0) z=v(i)%a/v(i)%b end where print*, z end real va, vb read*, va, vb z=va/vb print*, z endDraw a bar chart of 5 values entered by the user (>=0), where the y-axis is along the rowsand the x-axis is along the columns of the screen (as shown in the figure below).Function Prototype: void barChart(int N1, int N2, int N3, int N4, int N5)Example01:***********************************************************marks: 02Input:N1=>8 , N2=>6 , N3=>2 , N4=>10 , N5=>910 *09 * *08 * * *07 * * *06 * * * *05 * * * *04 * * * *03 * * * *02 * * * * *01 * * * * *1 2 3 4 5 Note: Take input in main function. don't use arrays or any other library other than iostream.Draw a bar chart of 5 values entered by the user (>=0), where the y-axis is along the rowsand the x-axis is along the columns of the screen (as shown in the figure below).Function Prototype: void barChart(int N1, int N2, int N3, int N4, int N5)Example01:***********************************************************Input:N1=>8 , N2=>6 , N3=>2 , N4=>10 , N5=>910 *09 * *08 * * *07 * * *06 * * * *05 * * * *04 * * * *03 * * * *02 * * * * *01 * * * * *1 2 3 4 5 Example 02:***********************************************************marks: 02Input:N1=>8 , N2=>6 , N3=>0 , N4=>11 , N5=>711 *10 *09 *08 * *07 * * *06 * * * *05 * * * *04 * * * *03 * * * *02 * * * *01 * * * *1 2 3 4 5Example 03:***********************************************************marks: 02Input:N1=>4 , N2=>3 , N3=>1 , N4=>0 , N5=>004 *03 * *02 * *01 * * *1 2 3 4 5Note: Take input in main function.
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- C++ In this task, you are required to write a code that converts an Octal number into its equivalent Decimal value or vice versa. The user first selects the conversion choice by inserting 1 or 2. Choice 1 is followed by inserting an Octal integer and getting its Decimal equivalent value as an output. Choice 2 requires inserting a Decimal integer and prints out its Octal equivalent. The Octal numeral system, is the base-8 number system, and uses the digits 0 to 7, that is to say 10 octal represents 8 Decimal and 100 octal represents 64 Decimal. Convertion from an Octal integer into Decimal In the Decimal system, each number is the digit multiplied by 10 to the power of its location (starting from 0). For example: 74 decimal = 7 x 10^1 + 4 x 10^0 1252 decimal = 1 x 10^3 + 2 x 10^2 + 5 x 10^1 + 2 x 10^0 each number is the digit multiplied by 8 to the power of its location (starting from 0). For example: 112 octal = 1 x 8^2 + 1 x 8^1 + 2 x 8^0 Converting an Octal integer into…Consider the following statements: Which of the following statements are valid? If they are invalid, explain why. (4) a. volume = box (length, width, height); b. volume = box (length, 3.8, height); c. cout << box(num1, num3, num2) << endl; d. cout << box (length, width, 7.0) << endl; e. volume = box (length, num1, height); f. cout << box(6.2, , height) << endl; g. volume = box (length + width, height) h. volume = box (num1, num2 + num3) ;The last part of this code I need the "cans" to be a whole number. I don't know how to change it What I have right now below: #include <iostream>#include <cmath> // Note: Needed for math functions in part(3)#include <iomanip> // For setprecisionusing namespace std; int main(){double wallHeight;double wallWidth;double wallArea; cout << "Enter wall height (feet):" << endl;cin >> wallHeight; // FIXME (1): Prompt user to input wall's widthcout << "Enter wall width (feet):" << endl;cin >> wallWidth; // Calculate and output wall areawallArea = wallHeight * wallWidth; // FIXME (1): Calculate the wall's area cout << fixed << setprecision(2) << "Wall area: " << wallArea<< " square feet" << endl;// FIXME (1): Finish the output statement // FIXME (2): Calculate and output the amount of paint in gallons needed to//paint the wallcout << fixed << setprecision(2) << "Paint needed: " <<…
- Modify the C# code given below so that the output of the program is y=5. Note: You can make changes only in line 4 and 12. Do, not hardcode the output. using System;class Solution { public void func(int y){ y = 5; }} class Sol{ static void Main(){ int y = 4; Solution s = new Solution(); s.func(out y); Console.WriteLine("y = {0}", y);}}Ask the user for a name and for a list of test scores. Show the number of tests taken and the average. Allow the user to enter any number of scores and make the program end when a negative value is entered. Write in java and use test case examples as a result.Examine the following code segment. What will be printed? If there are any errors indicate the nature of the error. int a[9] = { 1, 12, 3, 14, 25, 16, 7, 8, 9 }; int *ptr ; ptr = & a[ 2 ] ; for( i = 1; i <= 5; i = i + 2) cout << a[i] << *( ptr + i ); cout << ” ” << a[0] << ” ” << *ptr << ” ” << *ptr - 1 << ” ” << *(ptr - 2));