Question

Asked Jul 1, 2019

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What percentage of hospitals provide at least some charity care? Based on a random sample of hospital reports of eastern states, the following information is obtained (units in percentage of hospitals providing at least some charity care):

57.4 56.4 53.2 65.6 59.0 64.7 70.1 64.7 53.5 78.2

Assume that the population x values an approximetely normal distribution.

a) Use a calculater with mean and sample deviation keys to find the sample mean percentage x bar and sample standard deviation s. ( Round answers to one decimal place)

A) x bar= _____________%

s =_______________%

B) Find a 90% Confidence Interval for the population average Mu of the percentage of hospitals providing at least some charity care. (Round to one decimal place.)

Lower Limit_______________%

Upper Limit_______________%

1 Rating

Step 1

**Finding the mean and standard deviation of the variable***X*.

*Mean:*

The general formula to obtain the mean of a random variable is,

Mean = (Sum of *X *values)*/n.*

In columns of A1:A10 in Excel, enter the sample data.

In column B1, enter the Excel function “=AVERAGE(A1:A10)”.

The mean of the variable *X *is obtained as **62.3** % from the calculations given below:

Step 2

*Standard deviation:*

The general formula to obtain the standard deviation of a random variable is,

*s *= sqrt (sum of values of *X*^{2 }*/n* – (mean)^{2} ).

In column B2, enter the Excel function “=STDEV(A1:A10)”.

The standard deviation of a random variable *X *is obtained as **7.9** % from the calculations given below:

Step 3

**B.Computing the 90% confidence interval for population mean:**

**Confidence interval:**

The (1-α) % confidence i...

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