What volume of water vapor in liters could be generated at 1.053 atm and 443. K by the combustion of 233.46 grams of oxygen gas excess pentane gas (C5H12)? C5H12(g) + 8 O2(g) 5 CO2(g) + 6 H20(g) ---> (OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g") 0.08206L atm mol K R Do not type units with your answer Your Answer:

What volume of water vapor in liters could be generated at 1.053 atm and 443. K by the combustion of 233.46 grams of oxygen gas excess pentane gas (C5H12)? C5H12(g) + 8 O2(g) 5 CO2(g) + 6 H20(g) ---> (OR C5 H12 ("g") + 8 O2 ("g") right arrow 5 C O2 ("g") + 6 H2 O ("g") 0.08206L atm mol K R Do not type units with your answer Your Answer:

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter6: The Gaseous State

Section: Chapter Questions

Problem 6.59QE: What volume, in milliliters, of hydrogen gas at 1.33 atm and 33 C is produced by the reaction of...

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