when 0.0300 mol of NH3(g) react with 0.0200mol of N2O(g) according to the following equation? 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(l) ∆H0= -1010KJ Calculate the enthalpy of formation of ammonia ∆Hf (H2O) = -285.5 ∆Hf (N2O) = 81.6 ∆Hf (N2) = 0

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