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When 440 junior  college students were surveyed , 200 said they have a passport. Construct a 95 % confidence interval for the proportion of junior college students that have a passport. Assume the junior college enrolled 30,000 students. Round to the nearest thousandth.A]Compute the value of p(^) over the p.B]Determine the np(1-p)>to equal to 10 and n< equals 0.05 NC] Find the lower and upper bound of the confidence intervalD]Interpret the confidence interval

Question

When 440 junior  college students were surveyed , 200 said they have a passport. Construct a 95 % confidence interval for the proportion of junior college students that have a passport. Assume the junior college enrolled 30,000 students. Round to the nearest thousandth.

A]Compute the value of p(^) over the p.

B]Determine the np(1-p)>to equal to 10 and n< equals 0.05 N

C] Find the lower and upper bound of the confidence interval

D]Interpret the confidence interval

 

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Step 1

hello there! I see that there are more than three subparts in the question. According to our policies can answer only three subparts. Do find the solution for parts a,b,c. If you have any doubts in remaining parts make a new request.

Step 2

Given out 440 students 200 students said they have passport.

Proportion of students with passport = 200/440 = 0.4545, we say p = 0.45 (rounding to two decimals)

Step 3

here given total students enrolled in junior college = n = 30000

so n*p = 440*0.45  = 200 which is greater t...

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