Asked Sep 19, 2019

When 47.9 J of heat is added to 13.8 g of a liquid, its temperature rises by 1.70 ∘C.

What is the heat capacity of the liquid?



Expert Answer

Step 1


Heat (Q) = 47.9 J

Mass (m) of liquid = 13.8 g

Rise in temperature (△T) = 1.70 oC

Step 2

The heat capacity of the liqui...


Image Transcriptionclose

Q = mCAT 47.9 (J) 13.8 (g) x Cx 1.70 (°C) C 2.04 J/g-°C


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Chemical Thermodynamics

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