When a sample of 4-heptanone was irradiated for 150 s with 315nm radiation with a power output of 60 W under conditions of total absorption, it was found that 3.8 mmol CH; was formed. What is the quantum yield for the formation of ethene?
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- Instrumental studies involve the calculation of the instruments' limit of detection (LOD) in addition to the calibration curve. a. What exactly is LOD? b. Why is it necessary to determine it? c. Hpw is it determined?What is ΔSsurr for a reaction at 19 °C with ΔHsys = -7.3 kJ mol-1 ? Express your answer in J mol-1 K-1 to at least two significant figures.When a sample of 4-heptanone was irradiated for 100 sec with 313 nm radiation with a power output of 50 W under conditions of total absorption, it was found that 2.8 mmole C2H4 was formed. What is the quantum yield for the formation of ethane?
- Predict relative intensities at m/z 34, 35, and 36 for H2S. Let the intensity of the molecular ion be 100 and disregard contributions ,0.1%.Below is given the FT-IR (Fourier Transform Infra Red) data of a 1:1 (by weight) mixture of ethylene carbonate (EC) and dimethyl carbonate (DMC). Absorbance Pis given as a function of wavenumber, m. Regress the above data to a second order polynomial P = a, + a, m+ az m? Find the absorbance at m = 1000 cm-1 Wavenumber, m Absorbance, P (arbitrary unit) ( cm-1) 804.184 0.1591 827.326 0.0439 846.611 0.0050 869.753 0.0073 889.038 0.0448 892.895 0.0649 900.609 0.1204(a) A sample of body serum is to be analysed for sodium by flame emission spectroscopy. 1.00cm3 aliquot of serum was pipetted into each of two 50.0 cm3 volumetric flasks. The firstflask was diluted to volume with deionised water. The absorbance of this first solution was0.350. To the second flask 10.0 cm3 of a 25.0 ppm sodium standard was added and theflask made up to volume with deionised water. The absorbance of this second solution was0.720.(i) Calculate the concentration of the sodium in the body serum in mg dm–3
- Calculate the resolution required to resolve the following peaks; i) CH3N+ (MW = 28.0187) and N2+ (MW = 28.0061) ii) C2H4+ (MW = 28.0313) and CO+ (MW = 27.9949) iii) C3H7N3+ (MW = 85.0641) and C5H9O+ (MW = 85.0653) iv) 116Sn+ (At W = 115.90219) and 232Th2+ (At W = 232.03800)For an enzyme reaction followed spectrophotometrically at 340 nm the Vmax was calculated at 0.14 ∆A340/min (ε340 = 5.22 mM-1.cm-1). The 1 mL reaction in a 1 cm cuvette contained 30 ng of an enzyme (Mr of 100 000 g/mole). Calculate the Kcat for this enzyme.The molecule with strong absorptions at 1800 and 1760 cm ^ -1 is:
- Calculate delt g for Pbl2(s) + Pb2+(aq) +2I-(aq) T= 25C Kp= 8.7x10-9A sample of body serum is to be analysed for sodium by flame emission spectroscopy. 1.00cm' aliquot of serum was pipetted into each of two 50.0cm' volumetric flasks. The first flask was diluted to volume with deionised water. The absorbance of this first solution was0.350. To the second flask 10.0 cm' of a 25.0 ppm sodium standard was added and the flask made up to volume with deionised water. The absorbance of this second solution was 0.720.(i) Calculate the concentration of the sodium in the body serum in mg dm-3.Please refer to the images as much as you need to. For the following hydrocarbons, pick out 5 wavenumbers for each hydrocarbon, and give it its probable assignment for its structure. You may find this link useful: https://www.sigmaaldrich.com/US/en/technical-documents/technical-article/analytical-chemistry/photometry-and-reflectometry/ir-spectrum-table o-xylene (cm-1) : 985.76, 1021.06, 1052.51, 1119.30, 1383.43, 1465.62, 1495.11, 1604.66, 2859.82, 2874.76, 2922.19, 2937.08, 2968.08, 3016.57, 3049.67, 3063.02, 3105.51 m-xylene (cm-1) : 876.16, 904.28, 1039.26, 1094.05, 1169.56, 1376.70, 1397.17, 1458.12, 1491.51, 1538.93, 1557.96, 1591.83, 1612.18, 1652.69, 2730.72, 2863.59, 2920.44, 2944.72, 3015.77, 3104.24 p-xylene (cm-1) :1023.01, 1042.16, 1102.92, 1119.19, 1219.51, 1378.51, 1455.91, 1515.82, 1557.92, 1631.57, 1889.80, 2732.29, 2868.22, 2921.93, 2976.07, 2999.25, 3018.79, 3044.59, 3093.20, 3133.55, 3134.26