When potassium chloride, KCl, is added to a solution of lead nitrate, Pb(NO3)2, a bright yellow precipitate is formed, PbCl2. The chemical equation for this reaction is: Pb(NO3)2(aq) + 2 KCl(aq) ==> PbCl2(s) + 2 KNO3(aq) What volume of a 1.00 M KCl solution must you add to 75 mL of a 0.2 M solution of Pb(NO3)2 to precipitate out all of the Pb2+ ions? (You can assume quantitative conversion of Pb2+ and Cl- to PbCl2.)

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