When QS1 = 0 and QSO = 1, then which of the following is true O a. Subsequent byte is fetched from instruction queue O b. No operation O. queue is emptied O d. first byte of opcode is fetched from instruction queue
Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Correct Option is B⇒ 0010_1011
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A: According to the information given:- When MOV AL, 0D4h SHR AL, 1
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A: Ans:) The answers are given below.
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A: Required:
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Q: When QS1 = 0 and QS0 1, then which of the following Is Oa. No operation O b. first byte of opcode is…
A: Lets see the solution.
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A: Answer: We have explain in very well for given question
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A: REP Prefix: REP is used as a prefix to other instructions. REP prefixed instruction will be…
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A: Answer:
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A: ROtate Left (ROL) a bit manipulation instruction from the instruction set of 8086 microprocessor.…
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A: The effect of executing the following two 8051 instructions is: MOV C, PSW.0 MOV 13H, C
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Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: The SHR command is an abbreviation for 'Right Shift'. This command simply moves the bits mentioned…
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Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Your answer is given below with an explanation.
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A: Actually, AR is a Address Register.
Q: After the SHR instruction is executed in the code sequence below, what is the final value for AL?…
A: Correct Option is B⇒ 0010_1011
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A: The answer is given below:--
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A: Q1/A
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- Modify below program to include response timeProgram:ROUND ROBIN CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int i,j,n,bu[10],wa[10],tat[10],t,ct[10],max; float awt=0,att=0,temp=0;printf("Enter the no of processes--"); scanf("%d",&n);for(i=0;i<n;i++){printf("\nEnter Burst Time for process %d--", i+1); scanf("%d",&bu[i]);ct[i]=bu[i];}printf("\nEnter the size of time slice--"); scanf("%d",&t);max=bu[0];for(i=1;i<n;i++)if(max<bu[i])max=bu[i];for(j=0;j<(max/t)+1;j++)for(i=0;i<n;i++)if(bu[i]!=0)if(bu[i]<=t){tat[i]=temp+bu[i];temp=temp+bu[i];bu[i]=0;}else{bu[i]=bu[i]-t;temp=temp+t;}for(i=0;i<n;i++){wa[i]=tat[i]-ct[i];att+=tat[i];awt+=wa[i];}printf("\nThe Average Turnaround time is--%f",att/n);printf("\nThe Average Waiting time is--%f ",awt/n);printf("\n\tPROCESS\t BURST TIME \t WAITING TIME\tTURNAROUND TIME\n");for(i=0;i<n;i++)printf("\t%d \t %d \t\t %d \t\t %d…Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n); for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}Modiflow y the beprogram given to include response time program;FCFS CPU SCHEDULING ALGORITHM #include<stdio.h>#include<conio.h>main(){int bt[20], wt[20], tat[20], i, n; float wtavg, tatavg;clrscr();printf("\nEnter the number of processes -- "); scanf("%d", &n);for(i=0;i<n;i++){printf("\nEnter Burst Time for Process %d -- ", i); scanf("%d", &bt[i]);}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0];for(i=1;i<n;i++){wt[i] = wt[i-1] +bt[i-1];tat[i] = tat[i-1] +bt[i]; wtavg = wtavg + wt[i]; tatavg = tatavg + tat[i];}printf("\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n");for(i=0;i<n;i++){printf("\n\t P%d \t\t %d \t\t %d \t\t %d", i, bt[i], wt[i], tat[i]);}printf("\nAverage Waiting Time -- %f", wtavg/n);printf("\nAverage Turnaround Time -- %f", tatavg/n); getch();}
- 8.fast please in assembly You are giving the before condition and an instruction. Give the after condition:Before:Esp:00 63 FB 54instruction: ret After: Group of answer choices esp: 00 63 FB 50 esp: 00 63 FB 55 esp: 00 63 FB 54 esp: 00 63 FB 58Consider Context Switch time of 2 secs and modify below program accordingly Program: ROUND ROBIN CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int i,j,n,bu[10],wa[10],tat[10],t,ct[10],max; float awt=0,att=0,temp=0;printf("Enter the no of processes--"); scanf("%d",&n);for(i=0;i<n;i++){printf("\nEnter Burst Time for process %d--", i+1); scanf("%d",&bu[i]);ct[i]=bu[i];}printf("\nEnter the size of time slice--"); scanf("%d",&t);max=bu[0];for(i=1;i<n;i++)if(max<bu[i])max=bu[i];for(j=0;j<(max/t)+1;j++)for(i=0;i<n;i++)if(bu[i]!=0)if(bu[i]<=t){tat[i]=temp+bu[i];temp=temp+bu[i];bu[i]=0;}else{bu[i]=bu[i]-t;temp=temp+t;}for(i=0;i<n;i++){wa[i]=tat[i]-ct[i];att+=tat[i];awt+=wa[i];}printf("\nThe Average Turnaround time is--%f",att/n);printf("\nThe Average Waiting time is--%f ",awt/n);printf("\n\tPROCESS\t BURST TIME \t WAITING TIME\tTURNAROUND TIME\n");for(i=0;i<n;i++)printf("\t%d \t %d \t\t %d \t\t %d…Consider Context Switch time of 2 secs and modify below program accordingly Program: SJF CPU SCHEDULING ALGORITHM: #include<stdio.h>#include<conio.h>using namespace std; int main(){int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg;printf("\nEnter the number of processes--"); scanf("%d", &n);for(i=0;i<n;i++){p[i]=i;printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]);}for(i=0;i<n;i++)for(k=i+1;k<n;k++)if(bt[i]>bt[k]){temp=bt[i]; bt[i]=bt[k];bt[k]=temp;temp=p[i];p[i]=p[k];p[k]=temp;}wt[0] = wtavg = 0; tat[0] = tatavg = bt[0]; for(i=1;i<n;i++){wt[i] =wt[i-1]+bt[i-1];tat[i] =tat[i-1]+bt[i];wtavg = wtavg + wt[i];tatavg = tatavg + tat[i];}printf("\n\t PROCESS \tBURST TIME \t WAITING TIME\t TURNAROUND TIME\n"); for(i=0;i<n;i++)printf("\n\t P%d \t\t %d \t\t %d \t\t %d", p[i], bt[i], wt[i], tat[i]);printf("\nAverage Waiting Time--%f", wtavg/n);printf("\nAverage Turnaround Time--%f", tatavg/n); getch();}
- In a dual core processor, consider first four letters of your name coming as processes each having size equal to its ASCII code in MBs. Size of memory is 250 MB. Write down the sequence of using ready queue, wait queue. If a vowel comes in these letters, an interrupt of I/O will be generated Note: My Name is Razzaq .25: . Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore the time delay due to the first and last instruction. DELAY: LDI R16, 30 AGAIN: LDI R17, 35 HERE: NOP NOP DEC R17 BRNE HERE DEC R16 BRNE AGAIN RET 26: Write a program to display 2 on 7 segment. A 7 segment is connected to PortD.Consider Context Switch time of 2 secs and modify below program accordingly. SJF CPU SCHEDULING ALGORITHM #include<stdio.h> #include<conio.h> using namespace std; int main() { int p[20], bt[20], wt[20], tat[20], i, k, n, temp; float wtavg, tatavg; printf("\nEnter the number of processes--"); scanf("%d", &n); for(i=0;i<n;i++) { p[i]=i; printf("Enter Burst Time for Process %d--", i); scanf("%d", &bt[i]); } for(i=0;i<n;i++) for(k=i+1;k<n;k++) if(bt[i]>bt[k]) { temp=bt[i]; bt[i]=bt[k]; bt[k]=temp; temp=p[i]; p[i]=p[k];…
- Please answer the following with the reference; 1a. What is the purpose of the movq 0x10 (%rdi), rbp instruction here (at the C level or higher)? How does this relate to the earlier call to pushq rbp? 1b. Alice just remembered that the original C code had the following structure! Using what you now know about mystery, fill in the blanks with C code. long mystery ( TreeNode* t){ If ( ) { return ; } return }Create a stack-based program which computes: 7 & (9 | 8). Your answer should include an illustration which shows the state of the stack after each instruction and show the workings of all the calculations that are required.The control signal Ep or iEnableoutput allows the program counter to decrement its value. True False The control signal Ep or iEnableoutput sends the content of the program counter to the W bus. True False A tri-state buffer is needed for all data going to the W bus. True False In using 'assign' statement in Verilog, the left hand side must always be a register. True False In declaring a register in Verilog, the following format must be followed: reg [LSB:MSB] identifier; True False
