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In the figure below, what should be in the blue boxes for IR and MAR, respectively? Start Example 1 Is next instruction Yes The execution path would depend on the right instruction MAR-PC No memory in IBR? Fetch access cyde MBR-MMAR) required Arithmetie-logk unit (ALU) Left Instruction Yes IBR-MBR (20:39) IR-MBR (0:7) MAR-MBR (8:19) AC IR- MAR IR -MBR (20:27) MAR - MBR (28:39) required Input- Arithmetie-deg output equipment creuits MBR ??? Decode instruction in IR IFAC>0 then go to MOX, :19 PC-PC+1 Go to MCX, 0:19) AC-AC + MOX) lastretio AC-MIX) and data Execution Yes Is AC >0? ode MBR-M(MAR) PC-MAR MBR-MOMAR) Main memory M IR MAR AC--MBR AC-AC + MBR Contrud Contrl circeits Addreses M(X) = contents of memory location whose address is X j bits i through j Program control unit

In the figure below, what should be in the blue boxes for IR and MAR, respectively? Start Example 1 Is next instruction Yes The execution path would depend on the right instruction MAR-PC No memory in IBR? Fetch access cyde MBR-MMAR) required Arithmetie-logk unit (ALU) Left Instruction Yes IBR-MBR (20:39) IR-MBR (0:7) MAR-MBR (8:19) AC IR- MAR IR -MBR (20:27) MAR - MBR (28:39) required Input- Arithmetie-deg output equipment creuits MBR ??? Decode instruction in IR IFAC>0 then go to MOX, :19 PC-PC+1 Go to MCX, 0:19) AC-AC + MOX) lastretio AC-MIX) and data Execution Yes Is AC >0? ode MBR-M(MAR) PC-MAR MBR-MOMAR) Main memory M IR MAR AC--MBR AC-AC + MBR Contrud Contrl circeits Addreses M(X) = contents of memory location whose address is X j bits i through j Program control unit

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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1. MBR (20:27) and MBR (28:39)
 
2. IBR (0:7) and IBR (8:19)
 
3. IBR (20:27) and IBR (28:39)
 
4. MBR (0:7) and MBR (8:19)
In the figure below, what should be in the blue boxes for IR and MAR, respectively? Start Example 1 Yes Is next The execution path would depend on the right instruction instruction MAR-PC No memory in IBR? Fetch access cycle required MBR-MMAR) Arithmetie-logke unit (ALU) Left instruction required Yes IBR-MBR (20:39) IR -MBR (0:7) MAR-MBR (S:19) No IR -MBR (20:27) AC мо IR - MAR MAR-MBR (28:39) Input- output equipment Arithmetie-legie circuits MBR PC-PC +1 Decode instruction in IR ??? AC-AC + MEX) AC- M(X) Go to M(X, 0:19) IF AC >0 then lastructions and data go to MCX, 0:19 Execution Yes Is AC >0? cycle IBR PC MBR-M(MAR) PC-MAR MBR-M(MAR) Main memory IR MAR M AC-MBR AC-AC + MBR Contrd Control circuits signals Addresses M(X) = contents of memory location whose address is X (ij) = bits i through j Program control unit
Transcribed Image Text:In the figure below, what should be in the blue boxes for IR and MAR, respectively? Start Example 1 Yes Is next The execution path would depend on the right instruction instruction MAR-PC No memory in IBR? Fetch access cycle required MBR-MMAR) Arithmetie-logke unit (ALU) Left instruction required Yes IBR-MBR (20:39) IR -MBR (0:7) MAR-MBR (S:19) No IR -MBR (20:27) AC мо IR - MAR MAR-MBR (28:39) Input- output equipment Arithmetie-legie circuits MBR PC-PC +1 Decode instruction in IR ??? AC-AC + MEX) AC- M(X) Go to M(X, 0:19) IF AC >0 then lastructions and data go to MCX, 0:19 Execution Yes Is AC >0? cycle IBR PC MBR-M(MAR) PC-MAR MBR-M(MAR) Main memory IR MAR M AC-MBR AC-AC + MBR Contrd Control circuits signals Addresses M(X) = contents of memory location whose address is X (ij) = bits i through j Program control unit
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