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- A public water supply was found to contain 0.8 partper billion (ppb) by mass of chloroform, .(a) How many molecules would be present in a350 mL glass of this water? (b) If the in part (a)could be isolated, would this quantity be detectable onan ordinary analytical balance that measures masswith a precision of g?A(n) ___________ property describes the behavior of asubstance when it reacts or combines with anothersubstance.Why do you multipy the # of H2S mols by 4, when 4 corresponds to the reactory amount of O2?The logic there is somewhat confusing to me.I understand how/why you found out the mols of the equation but dividing the sample's MM by the equation confuses me.
- Determine the percentage Fe in a sample of limonite from the following data:Sample : 0.5000g ; KMnO4 used = 50.00 ml ; 1.000ml of KMnO4 is equivalent 0.005317 g Fe,FeSO4 used = 6.00 ml; 1.000ml FeSO4 is equivalent 0.009200 g FeO ( ans 44.59 %)An aqueous waste stream that has a maximum concentrationof 0.50 M H₂SO₄ (d=1.030 g/mL at 25C) will be neutralized by controlled addition of 40% caustic soda (NaOH; d=1.430 g/L) before it goes to the process sewer and then to the chemical plant waste treatment facility. However, a safety re-view finds that the waste stream could meet a small stream of animmiscible organic compound, which could form a flammable vapor in air at 40.°C. The maximum temperature of the causticsoda and the waste stream is 31°C. Could the temperature in-crease due to the heat of neutralization cause the vapor to ex-plode? Assume the specific heat capacity of each solution is 4.184 J/gK.Oxygen is soluble in water, much to the benefit of aquatic life forms. At 25 °C, the solubility of oxygen is about 7×10–6 g/cm3, and the pressure of O2 is about 20% of the atmospheric pressure. Could the oxygen dissolved in water affect your experimental results significantly?
- Initial concentrations For mixture #1 (see p.15 for preparation), show the worked out calculations for the initial concentrations of .... The first questionIn a 15-cm. evaporating dish is placed 15.4 g. (0.10 mole) of finely powdered biphenyl (Note 1). The dish is set on a porcelain rack in a 30-cm. desiccator with a 10-cm. evaporating dish under the rack containing 39 g. (12 ml., 0.24 mole) of bromine. The desiccator is closed, but a very small opening is provided for the escape of hydrogen bromide (Note 2). The biphenyl is left in contact with the bromine vapor for 8 hours (or overnight). The orange solid is then removed from the desiccator and allowed to stand in the air under a hood for at least 4 hours (Note 3). At this point, the product weighs about 30 g. and has a melting point in the neighborhood of 152°. The crude 4,4'-dibromobiphenyl is dissolved in 75 ml. of benzene, filtered, and cooled to 15°. The resulting crystals are filtered, giving a yield of 23.4– 24.0 g. (75–77%) of 4,4'-dibromobiphenyl, m.p. 162–163° (Note 4). How large of a scale can this reaction be run safely? Is it expensive?Aleks data for AgBrO3 is 5.38 x 10^-5