Your engineering consulting firm has been sent the design for a simple piping system connecting two large water reservoirs (both at 10 °C) as shown in the accompanying figure. 2₁-19m ₁ Sharp-edged entrance, K₁ = 0.5 i) ii) -Control volume boundary -Standard elbow, flanged, K₁= 0.3 -90 m Gate valve, fully open K₁=0.2- P2₂₂ √₂ = 0 22₂2=4m a. Your client has informed you that this system is scheduled to operate for many years. Thus, they want you to determine the flow rate in the cast-iron 5" SCH80 piping for two conditions: The "best case" scenario where the piping is brand new. The "worst case" scenario (according to what is mentioned in Daugherty & Franzini's book Fluid Mechanics with Engineering Applications) where the piping has become all rusty on the inside. b. In order to eliminate the change in flow rate over time that you predict will happen in part a), a colleague suggests partially closing the gate valve when the piping is brand new and then gradually opening it as the piping becomes more and more rusty on the inside. By citing specific terms in the Bernoulli equation, give a brief explanation on how this technique works. c. Determine the gate valve loss coefficient that must be set to initially when the piping is brand new so that the flow rate of water matches the final conditions (i.e, when the piping has become all rusty on the inside and the gate valve is fully opened).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please solve using moody chart

Relative roughness & =
Surface
Copper, Lead, Brass, Aluminum (new)
PVC and Plastic Pipes
Epoxy, Vinyl Ester and Isophthalic pipe
Stainless steel
Steel commercial pipe
Stretched steel
Weld steel
Galvanized steel
Rusted steel (corrosion)
New cast iron
Worn cast iron
Rusty cast iron
Sheet or asphalted cast iron
Smoothed cement
Ordinary concrete
Coarse concrete
Well planed wood
Ordinary wood
e
D
Pipe roughness [=] length
Pipe diameter [=] length
Absolute Roughness - k
10³ (m)
0.001 -0.002
0.0015-0.007
0.005
0.015
0.045 -0.09
0.015
0.045
0.15
0.15-4
0.25 -0.8
0.8-1.5
1.5-2.5
0.01 -0.015
0.3
0.3-1
0.3-5
0.18-0.9
5
(feet)
3.3-6.7 106
0.5-2.33 10-5
1.7 10-5
5 10-5
1.5-3 104
5 10-5
1.5 104
5 104
5-133 104
8-27 104
2.7-510-3
5-8.3 10-3
3.33-510-5
1 10-3
1-3.33 10-3
1-16.7 10³
6-30 10-4
16.7 10-3
From Fluid Mechanics with
Engineering Applications
(Daugherty & Franzini):
39
"In planning for the future
capacities it must be recalled
that scale deposits will increase
the roughness and reduce the
cross-sectional area. For pipes
in water service, the absolute
roughness of old pipes (20
years and more) may increase
over that of new pipes by
threefold for concrete or
cement-lined steel, up to
twenty-fold for cast iron, and
even to forty-fold for
tuberculated wrought-iron and
steel pipe."
http://www.engineeringtoolbox.com/major-loss-ducts-tubes-d 459.html
Transcribed Image Text:Relative roughness & = Surface Copper, Lead, Brass, Aluminum (new) PVC and Plastic Pipes Epoxy, Vinyl Ester and Isophthalic pipe Stainless steel Steel commercial pipe Stretched steel Weld steel Galvanized steel Rusted steel (corrosion) New cast iron Worn cast iron Rusty cast iron Sheet or asphalted cast iron Smoothed cement Ordinary concrete Coarse concrete Well planed wood Ordinary wood e D Pipe roughness [=] length Pipe diameter [=] length Absolute Roughness - k 10³ (m) 0.001 -0.002 0.0015-0.007 0.005 0.015 0.045 -0.09 0.015 0.045 0.15 0.15-4 0.25 -0.8 0.8-1.5 1.5-2.5 0.01 -0.015 0.3 0.3-1 0.3-5 0.18-0.9 5 (feet) 3.3-6.7 106 0.5-2.33 10-5 1.7 10-5 5 10-5 1.5-3 104 5 10-5 1.5 104 5 104 5-133 104 8-27 104 2.7-510-3 5-8.3 10-3 3.33-510-5 1 10-3 1-3.33 10-3 1-16.7 10³ 6-30 10-4 16.7 10-3 From Fluid Mechanics with Engineering Applications (Daugherty & Franzini): 39 "In planning for the future capacities it must be recalled that scale deposits will increase the roughness and reduce the cross-sectional area. For pipes in water service, the absolute roughness of old pipes (20 years and more) may increase over that of new pipes by threefold for concrete or cement-lined steel, up to twenty-fold for cast iron, and even to forty-fold for tuberculated wrought-iron and steel pipe." http://www.engineeringtoolbox.com/major-loss-ducts-tubes-d 459.html
QUESTION 4
Your engineering consulting firm has been sent the design for a simple piping system connecting two large water
reservoirs (both at 10 °C) as shown in the accompanying figure.
2₁-19m ₁
i)
ii)
Sharp-edged
entrance, K₂ = 0.5
-Control
volume
туре II
Guess
e
boundary
9 m
a. Your client has informed you that this system is scheduled to operate for many years. Thus, they want you to
determine the flow rate in the cast-iron 5" SCH80 piping for two conditions:
The "best case" scenario where the piping is brand new.
The "worst case" scenario (according to what is mentioned in Daugherty & Franzini's book
Fluid Mechanics with Engineering Applications) where the piping has become all rusty on the
inside.
-Standard elbow,
flanged, K₁ = 0.3
f=
-90 m
b. In order to eliminate the change in flow rate over time that you predict will happen in part a), a colleague
suggests partially closing the gate valve when the piping is brand new and then gradually opening it as the
piping becomes more and more rusty on the inside. By citing specific terms in the Bernoulli equation, give a
brief explanation on how this technique works.
?
Gate valve,
fully open
K₁=0.2-
c. Determine the gate valve loss coefficient that must be set to initially when the piping is brand new so that the
flow rate of water matches the final conditions (i.e, when the piping has become all rusty on the inside and
the gate valve is fully opened).
~0
P₁ = P₂
V/₂=0
Zy
P₂₂ √₂ = 0
2₂=4m
e = 0.26mm = 0.00026m
Internal diameter = 0.41011 ft + 3.281
= 0.122m
Z₂
2
0.00026m = 0.00213
0.122m
2
Transcribed Image Text:QUESTION 4 Your engineering consulting firm has been sent the design for a simple piping system connecting two large water reservoirs (both at 10 °C) as shown in the accompanying figure. 2₁-19m ₁ i) ii) Sharp-edged entrance, K₂ = 0.5 -Control volume туре II Guess e boundary 9 m a. Your client has informed you that this system is scheduled to operate for many years. Thus, they want you to determine the flow rate in the cast-iron 5" SCH80 piping for two conditions: The "best case" scenario where the piping is brand new. The "worst case" scenario (according to what is mentioned in Daugherty & Franzini's book Fluid Mechanics with Engineering Applications) where the piping has become all rusty on the inside. -Standard elbow, flanged, K₁ = 0.3 f= -90 m b. In order to eliminate the change in flow rate over time that you predict will happen in part a), a colleague suggests partially closing the gate valve when the piping is brand new and then gradually opening it as the piping becomes more and more rusty on the inside. By citing specific terms in the Bernoulli equation, give a brief explanation on how this technique works. ? Gate valve, fully open K₁=0.2- c. Determine the gate valve loss coefficient that must be set to initially when the piping is brand new so that the flow rate of water matches the final conditions (i.e, when the piping has become all rusty on the inside and the gate valve is fully opened). ~0 P₁ = P₂ V/₂=0 Zy P₂₂ √₂ = 0 2₂=4m e = 0.26mm = 0.00026m Internal diameter = 0.41011 ft + 3.281 = 0.122m Z₂ 2 0.00026m = 0.00213 0.122m 2
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Where did you get these values from? Like the density, u?

Reynolds number, Re
=
pVD 999.7xVx0.122
μ
0.001306
=
=
93386.98 V
Transcribed Image Text:Reynolds number, Re = pVD 999.7xVx0.122 μ 0.001306 = = 93386.98 V
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