Which expression for YYY completes the code to output the number of non-space characters in the inp string? int num 03B !! int i; string str; getline (cin, str); for (i 0; i < str.length (); ++i) { if (YYY) ( num = num + 1; cout << num << endl; O str == O str.at (i) O !str.isdigit (at (i)) O str != str.at (i) !=
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- Fix the errors and find the lowest marks entered by the user struct std{string name;int reg_no;int marks[5];}s1;getline(cin,s1.name);cin>>s1.reg_no;for(int i =0;i<5;i++)cin>>s1.marks[i]Given string stringVal on one line, integer idxStart on a second line, and integer choiceLen on a third line, replace choiceLen characters with "1234", starting at index idxStart. Ex: If the input is: Fuzzy bear 3 4 then the output is: Fuz1234ear Note: Using a pre-defined string function, the solution can be just one line of code. #include <iostream>#include <string>using namespace std; int main() { string stringVal; int idxStart; int choiceLen; getline(cin, stringVal); cin >> idxStart; cin >> choiceLen; /* Your code goes here */ cout << stringVal << endl; return 0;}10.17: Morse Code Converter C++Morse code is a code where each letter of the English alphabet, each digit, and various punctuation characters are represented by a series of dots and dashes. Table 10-8 from the textbook shows part of the code. Write a program that asks the user to enter a string, and then converts that string to Morse code. Note that Morse code represents both upper and lower case letters so that both 'A' and 'a' will be converted to ".-". Input Validation.None. Instructor Notes: Note: You can use the Morse table in the book or this site (space isn't listed, but it is just mapped to a space). You will most certainly need to create two parallel arrays to map the characters to the Morse code strings.
- Zybook Lab highway_number = int(input())if(highway_number>=1 and highway_number<=99): if(highway_number%2==0): print("I-"+str(highway_number),"is primary, going east/west.") else: print("I-"+str(highway_number),"is primary, going north/south.") elif(highway_number>=100 and highway_number<=999): highway_number_string = str(highway_number) length = len(highway_number_string) rightmost_digits = int(highway_number_string[length-2:length]) if(rightmost_digits==0): print(highway_number,"is not a valid interstate highway number.") elif(rightmost_digits%2==0): print("I-"+str(highway_number),"is auxiliary, serving I-",rightmost_digits,"going east/west.") else: print("I-"+str(highway_number),"is auxiliary, serving I-",rightmost_digits,"going north/south.")else: print(highway_number,"is not a valid interstate highway number.") i am getting whitespace error on output : I-290 is auxiliary, serving I- 90 going…Given string userGreeting on one line and string userName on a second line, append a space to userGreeting. Then, append userName to userGreeting. Lastly, append a period to userGreeting. Ex: If the input is: Hey Wilma Lee then the output is: Hey Wilma Lee. #include <iostream>#include <string>using namespace std; int main() { string userGreeting; string userName; getline(cin, userGreeting); getline(cin, userName); /* Your code goes here */ cout << userGreeting << endl; return 0;}Given string userInput on one line and string endString on a second line, assign concatStr with the copy of userInput with endString appended. Ex: If the input is: Fuzzy bear !!! then the output is: Fuzzy bear!!! #include <iostream> #include <string> using namespace std; int main() { string userInput; string endString; string concatStr; getline(cin, userInput); getline(cin, endString); /* Your code goes here */ cout << concatStr << endl; return 0; }
- A 2-character string, inString, is read from input. Replace each alphabetic character in inString with '_'. Otherwise, inString is not changed. Ex: If the input is w5, then the output is: _5 #include <iostream>#include <string>#include <cctype>using namespace std; int main() { string inString; getline(cin, inString); /* Your code goes here */ cout << inString << endl; return 0;}PART E: ROTATE LEFTGiven a string str, print out a rotated left 2 version where the first 2 chars are moved to the end. Assume thestring length will be at least 2.Methods to use: substring(), length(), concat()Testing cases: Hello => lloHe java => vaja Hi => Hi code => deco cat => tca 12345 => 34512 Chocolate => ocolateCh bricks => icksb/*** Returns a new string that is filled with length number of BLANK characters (e.g., initGuess(5, "$") would return the String "$$$$$""* @param length* @param BLANK* @return a new string that is filled with length number of blank characters* */public static String initGuess(int length, char BLANK) {return "string";}
- 4. Word Separator:Write a program that accepts as input a sentence in which all of thewords are run together but the first character of each word is uppercase. Convert the sentence to a string in which the words are separated by spaces and only the first word starts with an uppercase letter. For example the string “StopAndSmellTheRoses.” would be converted to “Stop and smell the roses. *python codingFind errors in this code also: internalstatdchkPalindrome(string str) { for(int i = 0, j = str.Length - 1; i < str.Length / 2; i++, j--) { if(str[i] != str[j]) { flag = false; break; } } if(flag) { ome"); } else Console.ine("Not Palindrome"); }Two String values are passed as input. Find if the second string s2 is a substring of the first strings1. If it is, print the index of the first occurrence.Else print -1.Inputmake123India123Output4*/#include<iostream>#include<string.h>using namespace std;int isSubstring(string s1, string s2) { int temp,j; for(int i=0;s1[i]!='\0';i++) { j=0; if(s1[i]==s2[j]) { temp=i+1; while(s1[i]==s2[j]) { i++; j++; } if(s2[j]=='\0') { return temp-1; } else { i=temp; temp=0; } } } if(temp==0) return -1;} int main(int argc, char const *argv[]){ string s1,s2; getline(cin,s1); getline(cin,s2); int res = isSubstring(s1,s2); if(res==-1) cout<<res; else cout<<"Found at index: "<<res;.