Which of the following compounds is represented by this spectral data? L00 4000 so00 1000 sdo waVENURERLu 4,000 3,000 2,000 1,500 1,000 500 Cyclohexanone Aminobenzene O Butanoic acid O Benzaldehyde O Cyclohexyl-methanol O00 O 0
Q: 2,2,2-Triphenylacetophenone Infrared Spectrum 1.005 1.000 0.995 0.990 0.985 0.980 0.975 0.970 3750…
A: The required structure is:
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A: 1H NMR: s = singlet, d = dublet, t = triplet, q = quartet
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A: IR or Infrared spectroscopy is used to find out the functional group in the structure.
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A:
Q: 100 80- 60- 40- 20. 0. 4000 3500 3000 2500 2000 1500 1000 Wavenumber (cm") What information may be…
A: Note: 3050 cm-1 sp2 C-H stretch, 2900 cm-1 sp3 C-H stretch. Therefore the compound is olefin.
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A: Solution -
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Q: Common Name: Ethyl butyrate 'H NMR IUPAC Name: Ethyl butanoate Zoom Out CAS No.: 105-54-4 Solvent:…
A:
Q: Butyronitrile 1-hexyn-3-ol 2-ethyl-1-butene 4-pentenyl acetate L00 1000 2000 4000 NAVENUNSERI…
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Q: MASS SPECTRUM 100. 57 (100%) 80. 60.- 40.- M 20.- 0. 20. 40. 60. 80. 100. m/z a. 3-methylpentane b.…
A:
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A:
Q: 43 100 80- 60 27 29 28 40 41 42 39 20 58 15 0- 10 20 30 40 50 60 Mass/charge (mle) Relative…
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Q: Cera Jorge, Teddy, Sundus esp 3.90 209 1.00 Chemical Sht ppm) Ge Jorge Teddy Sunds p SPECTRUM TH
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A:
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- Which of these 3 compounds is the least basic: aniline, 2-propylamine and 1-(2-aminophenyl)ethenone.A student was trying to determine the identity of an unknown compound. The melting point of the compound was 117-118oC. The student narrowed the possible compound down to the following: Compound Melting Point Range acetanilide 113-115oC fluorene 114-116oC mandelic acid 120-122oC A second student, doing the same experiment as above, found that their melting point was 100-108oC. What is wrong with the student’s melting point? Propose two reasons why the melting point could be incorrect. View keyboard shortcutsWhich of the following substituent is an ortho/para-directing activator and an ortho/para-directing deactivator? a amino group b halogen group c nitro group d carboxyl group
- What are the safety hazards of these chemicals Acetic anhydride (108-24-7) Formic acid (64-18-60) Benzotriazole (95-14-7) N-Formylbenzotriazole (72773-04-7)Starting with benzene synthesize the amino acid phenylalanine 1. using the strecker approach 2. by reductive aminationWhat must be the starting material to carry out the following reaction? a) butanamide b) 4-aminobutanol c) 1-amino-2-butanone d) propanamide e) butanenitrile
- state whether the following statement is true or false. explain your answer. 1. pyridine is more basic than piperidine 2. pyridine is resonance stabilizedthe Infrared spectroscopy experiment by using(FTIR) to identify the unknow compound from the list : EthanolIsoamyl acetateHexanal1-PropanolAnisaldehydeValerophenoneBenzoic AcidCyclohexanonemethyl iso-butyl ketoneBenzyl alcoholPropionaldehydeBenzaldehydePhenylacetic acid3-methylcyclohexanoneMethanolEthyl acetatePinacolonewhich compound is represented in the picture ?The catalog prices for all reagents used to make Phenacetin are shown: p-ethoyxanaline: 100 grams, $26.00 (Weight used: 2.5 grams) Acetic Anhydride: 1000 grams, $39.50 (Weight used: 2.2 grams, Density: 1.08) Hydrochloric Acid: 2500 mL, $30.20 (Weight used: 1.53 grams, Density: 1.02) Sodium Acetate Trihydrate: 500 grams, $30.50 (Weight used: 3.0 grams) Calculate the cost of each reagent.
- Draw the structure that corresponds to the following data and the NMR spectrum shown. Formula: C6H12O2IR Spectrum shows intense stretches at 1730, 1220, and 1050 cm-1. These three IR signals indicate the presence of an ester functional group.E. explain each step with words on how to get the structure. Step 1: Calculate the Index of Hydrogen Deficiency (IHD). Step 2: Use IR to determine obvious functional groups. Step 3: Use 1H-NMR to determine structural details. Step 4: Confirm the final structure using 13C-NMR.Give reasons for the following:(i) Aniline does not undergo Friedal-Crafts reaction.(ii) (CH3)2 NH is more basic than (CH3)3 N in an aqueous solution.(iii) Primary amines have higher boiling point than tertiary amines.