Which of the following equations is incorrectly written? X v² = v² - 2aAd 1 Ad = ¾¡At + −— àAt² 2 + ad - (* = *) ^² At 2 1 Að = v₁At — -—-—ầAt² 2 – 2 V = V₁ + àAt
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Please help which is the correct out the two the x or the arrow. Do t worry about the question below it
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- An object is shot upwards from ground level with an initial velocity of 3 meters per second; its subject only to the force of gravity (no air resistamce). Find its maximum altitude and the time at which it hits the ground (g = 32fps^2 = 9.8mps^2) Choices: A) 1.184 meters, 0.61224 sec B) 0.4592 meter, 3.267 sec C) 0.9184 meter, 0.61224 sec D) 0.4592 meter, 0.61124 secWhile standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.61 m/s. The stone subsequently falls to the ground, which is 17.3 m below the point where the stone leaves his hand. At what speed does the stone impact the ground? Ignore air resistance and use ?=9.81 m/s2 for the acceleration due to gravity. A) Impact speed: _________________________ m/s B) How much time is the stone in the air? elapsed time: ____________ sA student’s book falls out the window of the physics laboratory. How long does it take to fall to the ground (20 m) below? With what velocity does the book hit the ground? Answer: (t=2.02s),(v=-19.8m/s)
- While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 7.39 m/s. The stone subsequently falls to the ground, which is 19.1 m below the point where the stone leaves his hand. At what speed does the stone impact the ground? Ignore air resistance and use ?=9.81 m/s2 for the acceleration due to gravity. impact speed: How much time is the stone in the air? elapsed time:A car is traveling at 50 mi/hmi/h down a highway. What magnitude of acceleration does it need to have to come to a complete stop in a distance of 200 ftft? Express your answer in miles per hour squared. What magnitude of acceleration does it need to stop in 200 ftft if it is traveling at 100 mi/hmi/h? Express your answer in miles per hour squared.A person can survive a feet-first impact at a speed of about 12 m/s (27 mi/h) on concrete; 15 m/s (34 mi/h) on soil; and 34 m/s (76 mi/h) on water. Why the different values for different surfaces?
- A landscape architect is planning an artificial waterfall in a city park. Water flowing at 1.70 m/s will leave the end of a horizontal channel at the top of a vertical wall h = 2.35 m high, and from there it will fall into a pool (Fig. P3.42). (a) Will the space behind the waterfall be wide enough for a pedestrian walkway? (b) To sell her plan to the city council, the architect wants to build a model to standard scale, which is one-twelfth actual size. How fast should the water flow in the channel in the model? Figure P3.42A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = t3 − 15t2 + 72t (a) Find the velocity at time t. v(t) = (b) What is the velocity after 5 s? v(5) = ft/s (c) When is the particle at rest? t = s (smaller value) t = s (larger value) (d) When is the particle moving in the positive direction? (Enter your answer in interval notation.) t (e) Find the total distance traveled during the first 8 s.ft(f) Find the acceleration at time t. a(t) = Find the acceleration after 5 s. a(5) = ft/s2 (g) Graph the position, velocity, and acceleration functions for the first 8 s. (h) When, for 0 ≤ t < ∞, is the particle speeding up? (Enter your answer in interval notation.) When, for 0 ≤ t < ∞, is it slowing down? (Enter your answer in interval notation.)When jumping, a flea accelerates at an astounding 1,000 m/s2 , but over only the very short distance of 0.5 mm. If a flea jumps straight up, and if air resistance is neglected (a rather poor approximation in this situation), how high does the flea go (write your answer in centimeters)? Acceleration due to gravity g= 9.8 m/s2.
- A rocket of mass 1223 kg accelerates at 129 m/s^2 for 39 s from an initial speed of 1836 m/s. How fast will be the rocket be traveling after 39 s? No unit is required for the final answer.A sports car driver turned his car 15.0 km [E 30.0° N], and then turned again 30.0 km [W 45.0° N] to get back on track. If the diversion lasted a total of 2.00 minutes, what was the average velocity of the car, in m/s? Include diagrams to help you solve the question.We did this problem in class (3.10) and the answer ended up being 1.35 m/s but I'm still confused with the steps taken to get that answer.