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- This is in c++ Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. Don't print the dummy head node. Example input : 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 output: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData() method// to print the entire linked list //…This is in c++ Given the MileageTrackerNode class, complete main() to insert nodes into a linked list (using the InsertAfter() function). The first user-input value is the number of nodes in the linked list. Use the PrintNodeData() function to print the entire linked list. Don't print the dummy head node. Example input : 3 2.2 7/2/18 3.2 7/7/18 4.5 7/16/18 output: 2.2, 7/2/18 3.2, 7/7/18 4.5, 7/16/18 main.cpp: #include "MileageTrackerNode.h"#include <string>#include <iostream>using namespace std; int main (int argc, char* argv[]) {// References for MileageTrackerNode objectsMileageTrackerNode* headNode;MileageTrackerNode* currNode;MileageTrackerNode* lastNode; double miles;string date;int i; // Front of nodes listheadNode = new MileageTrackerNode();lastNode = headNode; // TODO: Read in the number of nodes // TODO: For the read in number of nodes, read// in data and insert into the linked list // TODO: Call the PrintNodeData() method// to print the entire linked list //…Suppose a node of a linked list is defined as follows in your program: typedef struct{ int data; struct Node* link; } Node; Write the definition of a function, printOdd(), which displays all the odd numbers of a linked list. What will be the time complexity of printOdd()? Express the time complexity in terms of Big-O notation.
- Suppose a node of a linked list is defined as follows in your program: typedef struct{ char data; struct Node* link; } Node; Write the definitions of two functions (i) Node* pop(Node* top) – which removes the top element of the stack, and (ii) bool compare(Node* topA, Node* topB) - which returns true if the both stacks have identical data. The function returns false if the data in both stacks are not identical. In the function definitions, top, topA, and topB point the top elements of corresponding stacks. You must use the following function definitions in your answer. The peek function has already been defined. You need to write the definition of pop and compare functions. You are not allowed to modify the parameters and/or return types of the functions. Node* pop(Node* top){ //write the function definition } char peek(Node* top){ return top->data; } bool compare(Node* topA, Node* topB){ //write the function definition } Write the time complexity in Big-O notation…Question : Write a c++ program which creates a Linked List having maximum sum out of two Sorted Linked Lists. Use this : LinkedList finalMaxSumList(LinkedList List1, LinkedList List2); For eg: You have two sorted linked lists, create a linked list that contains data with maximum sum. The resulting list with maximum sum will contain nodes with data from both input sorted lists. While creating the resulting list with maximum sum, we may switch to the other input list only at the point of intersection (which mean the two nodes with the same value in the lists). You are only allowed to use O(1) extra space. Note: You have to returned Linked List which contain finalMaxSumList and you are not allowed to change in data type and prototype of the Function. Input:List1 = 1->3->30->90->120->240->511List2 = 0->3->12->32->90->125->240->249 Returned LinkedList: Following is resulting linked list out of two sorted listsResultingList =…write a c++ code that will do the adding a node to a doubly-linked list in the three cases (insert a node at the beginning-middle-end). A separate function is required for each case.
- Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function: void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support…Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function; void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support File…Suppose you have two objects of Doubly Linked List D1 and D2. Each object is representing a different Doubly Linked List. Write a function to concatenate both doubly linked lists. The concatenation function must return the address of head node of concatenated Doubly Linked List, and it must take two Node* parameters. You need to keep in mind all exceptional cases for example what if either one of the doubly linked lists is empty? Perform this task on paper, take a clear picture of solution and paste it in answer section.
- write a c++ code that will do the adding a node to a Doubly Linked-List in the three cases (insert a node at the beginning - middle - end ). Write a separate function for each case.Question : Write a c++ program which creates a Linked List having maximum sum out of two Sorted Linked Lists.For eg: You have two sorted linked lists, create a linked list that contains data with maximum sum. The resulting list with maximum sum will contain nodes with data from both input sorted lists. While creating the resulting list with maximum sum, we may switch to the other input list only at the point of intersection (which mean the two nodes with the same value in the lists). You are only allowed to use O(1) extra space. Input:List1 = 1->3->30->90->120->240->511List2 = 0->3->12->32->90->125->240->249 Output: Following is resulting linked list out of two sorted listsResultingList = 1->3->12->32->90->125->240->511Implement in C Programming 8.18.1: LAB: Simple linked list Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list starting at firstNode. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create() provided here differs from the code shown in the book. The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and IntNode_SumList(). main() reads 5 integers from a user: The number of nodes to be added to a new list The value of the first node of the list An increment between the values of two consecutive…