Which regular loop corresponds to this enhanced for loop? char[]vowels={'a','e','i','o','u'}; for (char item: vowels) { System.out.println(item); } a. for(inti=0;i
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Which regular loop corresponds to this enhanced for loop?
for (char item: vowels) {
System.out.println(item);
}
| a. |
for(inti=0;i<item;++i){
System.out.println(vowels[i]); }
|
|
| b. |
for(inti=0;i<item.length;++i){
System.out.println(vowels[i]); }
|
|
| c. |
for(inti=0;i<vowels.length;++i){
System.out.println(vowels[i]); } |
| d. |
for(inti=0;i<vowels.length;++i){
System.out.println(item[i]); } |
JAVA
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- This code gets an error for going out of range in the last for loop. What can I do to fix this? # Lucas Conklin# 5772707import csvimport statistics def readCSVIntoDictionary(f_name): data = [] with open(f_name) as f: reader = csv.reader(f) for row in reader: if not data: for index in range(len(row)): data.append([]) for index in range(len(row)): data[index].append(float(row[index])) f.close() return data features = readCSVIntoDictionary("C:\\Users\\lucas\\Downloads\\pima.csv")print(features) def find_median_and_SD(data, feature): med = statistics.median(data[feature]) rounded_med = round(med, 4) st_dev = statistics.stdev(data[feature]) rounded_st_dev = round(st_dev, 5) return rounded_med, rounded_st_dev for i in range(0, len(features)): (median, st_dev) = find_median_and_SD(features, i) print(f'Feature {i} Median: {median} Standard Deviation: {st_dev}')…You will also have to write Student Tests that test the following in the provided file.i. Adding element(s).ii. Get elements at index – (1) with a valid index and (2) with an invalid indexiii. Test equality of two StringArrayLists (of size 0, 2)iv. Test if a StringArrayList contains a String (test both true and false cases)v.Test removing a String from a StringArrayList.My question is to modify binary search to only display the result with book title with its ID number. Here is the code to modify: def search_books(self, book_title): # Remove leading and trailing white spaces and convert to lowercase book_title = book_title.strip().lower() # Extract book titles and IDs from self.books_dict book_titles = [value["books_title"].strip().lower() for key, value in self.books_dict.items()] #book_ids = list(self.books_dict.keys()) # Sort the book titles and IDs together book_titles, book_ids = zip(*sorted(zip(book_titles, book_ids))) #zip takes iterable or containers and return a single iterator # Perform binary search for the book title low = 0 high = len(book_titles) - 1 while low <= high: mid = (low + high) // 2 bt = book_titles[mid].replace('"', '') if bt == book_title: print(f"Book '{book_title}'…
- How could this program work without items() or enumerate? def Find_heights(data): heights = [] for d in data: city = d[1] height = float(d[2]) index = -1 for i, item in enumerate(heights): if item[0] == city: index = i break if index == -1: heights.append([city, [height]]) else: heights[index][1].append(height) return heights height_list = Find_heights(csv_data)print(height_list)# Output: [['New York', [5.8, 5.9, 6.0]], ['Los Angeles', [5.5, 5.6, 5.7]], ['Chicago', [5.9, 6.0, 6.1]], ['Houston', [5.6, 5.7, 5.8]]] #To remove the items from the Find_average function, you can modify it to return a dictionary with city names as keys and average heights as values. Here's an updated version of the function: def Find_average(heights_list): averages = {} for city_data in heights_list: city = city_data[0] heights = city_data[1] average = sum(heights) /…Write a program that keeps names and emails addresses in a dictionary as key-value pairs. First print all keys with their value using for loop.then the program should display a menu that lets user look up a person’s email address, add a new name and email address, change an existing email address and delete an existing name and email address (dictionary contains at least 10 names and emails)Here is the iterative implementation of binary search: For each call to binary_search below, indicate how many times the code inside the while loop will execute. animals = ["aardvark", "cat", "dog", "elephant", "panda"] 1. binary_search("elephant", animals) 2. binary_search("dog", animals) 3. binary_search("anteater", animals)
- add comments in code like what for loop doing what and other functions#include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIXint source,V,E,time,visited[20],G[20][20];void DFS(int i){int j;visited[i]=1;printf(" %d->",i+1);for(j=0;j<V;j++){if(G[i][j]==1&&visited[j]==0)DFS(j);}}int main(){int i,j,v1,v2;printf("\t\t\tGraphs\n");printf("Enter the no of edges:");scanf("%d",&E);printf("Enter the no of vertices:");scanf("%d",&V);for(i=0;i<V;i++){for(j=0;j<V;j++)G[i][j]=0;}/* creating edges :P */for(i=0;i<E;i++){printf("Enter the edges (format: V1 V2) : ");scanf("%d%d",&v1,&v2);G[v1-1][v2-1]=1; } for(i=0;i<V;i++){for(j=0;j<V;j++)printf(" %d ",G[i][j]);printf("\n");}printf("Enter the source: ");scanf("%d",&source);DFS(source-1);return 0;}What is printed as a result of executing the following code segment? List list1 = new ArrayList(); list1.add(new Integer(1)); list1.add(new Integer(2)); list1.add(new Integer(3)); list1.set(2, new Integer(4)); list1.add(2, new Integer(5)); list1.add(new Integer(6)); System.out.println(list1); [1, 5, 2, 4, 6] [1, 2, 4, 5, 6] [1, 2, 3, 4, 5] [1, 2, 5, 4, 6]The for loop iterates across the elements in a given list. Hence, it runs forever, provided there are still objects to process. Will this prove to be a true or untrue statement?