Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the element.Ex: lowerScores = {5, 0, 2, -3} becomes {4, 0, 1, 0}.324758.2040686.qx3zgy71 #include 23 int main(void) {const int SCORES SIZE = 4;int lowerScores[SCORES_SIZE];int i;457for (i = 0; i < SCORES_SIZE; ++i) {scanf("%d", &(lowerscores[i]));}89101112/* Your solution goes here */13for (i = 0; i < SCORES_SIZE; ++i) {printf("%d ", lowerScores[i]);}printf("\n");1415161718

Iterate over the given array If element is less than or equal to 0, we make it as 0 Else we decrease…

Answered: Write a loop that subtracts 1 from each…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes here */ return 0;}
Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. #include <iostream>using namespace std; int main() { const int SCORES_SIZE = 4; int bonusScores[SCORES_SIZE]; int i; for (i = 0; i < SCORES_SIZE; ++i) { cin >> bonusScores[i]; } /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) { cout << bonusScores[i] << " "; } cout << endl; return 0;}
Write a loop that sets each array element to the sum of itself and the next element, except for the last element which stays the same. Be careful not to index beyond the last element. Ex:Initial scores: 10, 20, 30, 40 Scores after the loop: 30, 50, 70, 40 The first element is 30 or 10 + 20, the second element is 50 or 20 + 30, and the third element is 70 or 30 + 40. The last element remains the same. #include <iostream>using namespace std; int main() {const int SCORES_SIZE = 4;int bonusScores[SCORES_SIZE];int i; for (i = 0; i < SCORES_SIZE; ++i) {cin >> bonusScores[i];} /* Your solution goes here */ for (i = 0; i < SCORES_SIZE; ++i) {cout << bonusScores[i] << " ";}cout << endl; return 0;} Please help me with this issue using c++.
Arrays Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() {const int NUM_VALS = 4;int courseGrades[NUM_VALS];int i; for (i = 0; i < NUM_VALS; ++i) {cin >> courseGrades[i];} /* Your…
I have given you the linear search code example on the video and I want you to go through the code and adjust the code. In the following code, list consists of number 4 twice however when you execute this code you find only the first 4. Please adjust your code to find both 4’s on the list def linear_search(list1,key): for i in range(len(list1)): if key==list1[i]: print("Element is found at index", i) break else: print("The element is not found") list1=[4,5,10,4,9,21] key=int(input("Enter a key number: ")) linear_search(list1,key)
in java when you use an enhanced for loop with an array, you don’t need to use a/an ________________ variable to iterate through the elements of the array.
Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i);…
detemine if the follow statement are true or False and why? screenshots show the ArrayBoundedStack class and StackUnderflowException code If N represents the number of elements on the stack, then the push method of the ArrayBoundedStack class is O(N). While processing this expression ( } ( ) ( ) { { { } [ ] } } ) the highest number of elements on our stack at any one time is 1. If N represents the maximum possible number of elements on the stack, then the ArrayBasedStack constructor is O(N). The following expression is balanced: ( ( ( [ ) ] ) ) Our StackUnderflowException code essentially consists of two simple constructors and "packages" and "extends" statements and nothing else.
In C programming In a main function declare an array of 1000 ints. Fill up the array with random numbers that represent the rolls of a die. That means values from 1 to 6. Write a loop that will count how many times each of the values appears in the array of 1000 die rolls. Use an array of 6 elements to keep track of the counts, as opposed to 6 individual variables. Print out how many times each value appears in the array. 1 occurs XXX times 2 occurs XXX times Hint: If you find yourself repeating the same line of code you need to use a loop. If you declare several variables that are almost the same, maybe you need to use an array. count1, count2, count3, count4, … is wrong. Make an array and use the elements of the array as counters. Output the results using a loop with one printf statement. This gets more important when we are rolling 2 dice.
JAVA Write an application containing three parallel arrays that hold 10 elements each. The first array hold four-digit student ID numbers, the second array holds first names, and the third array holds the students’ grade point averages. Use dialog boxes to accept a student ID number and display the student’s first name and grade point average. If a match is not found, display an error message that includes the invalid ID number and allow the user to search for a new ID number.
Variable t has been assigned a tuple whose elements are numbers. Write a code that uses while loop that counts the number of times the first element of the tuple appears in the rest of the tuple and assign the number to a variable named repeats. Code: the wrong message Solutions with this approach don't use comma t=(1,6,5,7,1,3,4,1) repeats=0 i=1 while i<len(t): if t[i]==t[0]: repeats+=1 i+=1
PLEASE HELP IN FUNCTIONAL PROGRAMMING CODE I have to insert a few lines to generate random numbers and for determining the time taken to get results (define (insert L M) (if (null? L) M (if (null? M) L (if (< (car L) (car M)) (cons (car L) (insert (cdr L) M)) (cons (car M) (insert (cdr M) L)))))) ;; Exp. (insertionsort '(4 2 10 3 -1 5)) ==> (-1 2 3 4 5 10) (define (insertionsort L) (if (null? L) '() insert (list (car L)) (insertionsort (cdr L))))) (define (random-list n) (unless (exact-nonnegative-integer? n) (raise-argument-error 'make-list "exact-nonnegative-integer?" 0 n)) (let loop ([n n] [r '()]) (if (zero? n) r (loop (sub1 n) (cons (random 2147483647) r))))) Sample function call:(insertionsort (random-list 10000))

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Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the element. Ex: lowerScores = {5, 0, 2, -3} becomes (4, 0, 1, 0}.