Suppose you want to make 500 mL of a 0.20 M Tris buffer at pH 8.0. On the shelf in your lab, you see a bottle of 1.0 M Tris at pH 6.8 and realize you can use this stock to make the new buffer. Assuming you have 5.0 M HCl and 5.0 M NaOH at your disposal, how much of each component would you need to add to make the 0.20 M Tris buffer at pH 8.0 from the 1.0 M Tris, pH 6.8 stock? (The pKa of Tris is 8.06.)
Suppose you want to make 500 mL of a 0.20 M Tris buffer at pH 8.0. On the shelf in your lab, you see a bottle of 1.0 M Tris at pH 6.8 and realize you can use this stock to make the new buffer. Assuming you have 5.0 M HCl and 5.0 M NaOH at your disposal, how much of each component would you need to add to make the 0.20 M Tris buffer at pH 8.0 from the 1.0 M Tris, pH 6.8 stock? (The pKa of Tris is 8.06.)
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 25QAP: A sodium hydrogen carbonate-sodium carbonate buffer is to be prepared with a pH of 9.40. (a) What...
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Suppose you want to make 500 mL of a 0.20 M Tris buffer at pH 8.0. On the shelf in your lab, you see
a bottle of 1.0 M Tris at pH 6.8 and realize you can use this stock to make the new buffer. Assuming you
have 5.0 M HCl and 5.0 M NaOH at your disposal, how much of each component would you need to add
to make the 0.20 M Tris buffer at pH 8.0 from the 1.0 M Tris, pH 6.8 stock? (The pKa of Tris is 8.06.)
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Why didn't the tris stock of pH 6.8 play more of a role in the calculations? Should it of have?
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