Why is a current divider expression considered a shortcut in circuit analysis?It allows you to find the current through an individual resistor using a singleexpression instead of writing a bunch of KCL/KVL equations and plugging theminto each other.Because if you divide anything, it is shorter than what you started with.

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Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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Using the supernode concept to determine the voltage marked v20 in the figure, the crossed wires that are not marked by a thick dot are not in physical contact.
i've already seen this solution. but regardless, i askedfor an explanation. i always have a big issue with understanding how to do nodal analysis in these type of circuits, how to name nodes and on what basis. how was the outgoing current 0-v0/3r and how do i identify it and in the incoming current. how to use voltage division rule here. so please annotate everything on the figure and help me understand all my above inquiries so i can understand how to solve these type of questions. thank you! please be extremely detailed and concise. also when can i and can i not use nodal analysis and voltae division rule
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A lead wire and an iron wire are connected in parallel. Their respective specific resistances are in the ratio 49: 24. The former carries 80 percent more current than the latter and the latter is 47 percent longer than the former. Determine the ratio of their cross sectional areas ROUND OFF TO THE NEAREST HUNDRETHS
Which of the following statements are correct for the circuit below? Thanks to the capacitors I – C1 and C2, the voltage gain of the circuit increases. II – Capacitors C1 and C2 are coupling capacitors and provide an isolation function between AC and DC voltages in the circuit. Thanks to the III – RE resistor, the voltage gain of the circuit increases. Thanks to the IV – RE resistor, the stability of the circuit increases. The V – C3 Capacitor is a bypass capacitor and prevents the loss of voltage gain. Capacitor VI – C3 is a coupling capacitor and has no effect on the voltage gain in the circuit. VII – As the value of the source internal resistance Rs increases, the voltage gain decreases. VIII – The voltage gain decreases as the value of any RL load to be added to the circuit increases
Subject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96W

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