Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ? Pka 1= 3.128 Pka 2=4.761 Pka 3= 6.396 Concentration of acid : 0,026 M Volume of acid : 50 ml Concentration of NaOh = 99,986mM

Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ? Pka 1= 3.128 Pka 2=4.761 Pka 3= 6.396 Concentration of acid : 0,026 M Volume of acid : 50 ml Concentration of NaOh = 99,986mM

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.15QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Why is the pH of the first, second and third equivalence point, of a titration of triprotic acid and NaOH ?

Pka 1= 3.128

Pka 2=4.761

Pka 3= 6.396

Concentration of acid : 0,026 M

Volume of acid : 50 ml

Concentration of NaOh = 99,986mM

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