will give thumbs up Python Big-O Coding Exercise Need solving and explanation Pls answer only if u know big-o
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Q: Python Big-O Coding Exercise Need solving and explanation Pls answer only if u know big-o
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Python
Big-O Coding Exercise
Need solving and explanation
Pls answer only if u know big-o
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- PYTHON PROGRAMMING Submit a code snippet for a function (in the coding sense) that accepts as an input a list of size n and prints all the integers from 1 up to n. This function must have complexity O(n^2). Hint: Efficiency isn't always the answer. Restraints that have corresponding deductions if not followed are listed below: You must only print each number once (-4/20) The algorithm/code function must have complexity to O(n^2) (-20/20) Update: It needs to be O( n^2 ) hence -20/20 The input must be a list not an integer (-4/20) Example: If the input is a list of size 4, the output is 1 2 3 4Please code the following in Python. Thanks. I'll give upvote if correct. Make a Big-O function that accepts, as an input, a list of size n and prints all the integers from 1 up to n. Follow the restrictions that are enumerated below: You must only print each number once (-4/20) The algorithm/code function must have complexity to O(n^2) (-20/20). It needs to be O(n^2) hence -20/20. The input must be a list not an integer (-4/20). An example of this is if the input is a list of size 4, the output is: 1 2 3 4code in scala def unfold[A, S](z: S)(f: S => Option[(A, S)]): LazyList[A] = f(z) match { case Some((h, s)) => h #:: unfold(s)(f) case None => LazyList() } A positive integer is perfect if it equals the sum of all of its factors, excluding the number itself. For example, 6, 28, 496, and so on. Define a LazyList to generate an infinite list of perfect numbers. Use higher-order functions whenever possible. [Hint: One way to do this is by (1) having one function construct a list of factors (use unfold and filter for this), (2) having another function which folds the list of factors into their sum, and (3) creating a LazyList using unfold, filter and the previously constructed functions.] e number itself. For example, 6, 28, 496, and so on. Define a LazyList to generate an infinite list of perfect
- The sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). In python, implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. See template code attached.Implement the sieve of Eratosthenes: a function for computing prime numbers, known to the ancient Greeks. Choose an integer n. This function will compute all prime numbers up to, and including, n. First insert all numbers from 1 to n into a set. Then erase all multiples of 2 (except 2); that is, 4, 6, 8, 10, 12, ... . Erase all multiples of 3, that is, 6, 9, 12, 15, ... . Go up to ?⎯⎯√n. The remaining numbers are all primes. Make sure that you use functions in your solution, including a main function. Define def sieveOfEratosthenes(n) that receives the maximum value and returns a list of all prime numbers less than or equal to this value in main() print the list of prime numbers.BIG-O!!Make a code snippet for a function (in the coding sense) that accepts as an input a list of size n and prints all the integers from 1 up to n. This function must have complexity O(n^2) Hint: Efficiency isn't always the answer. Restraints: You must only print each number once The algorithm/code function must have complexity to O(n^2) The input must be a LIST not an integer. Example: If the input is a list of size 4, the output is 1 2 3 4
- PYTHON: create a function code(n) that sorts a list of words alphabetically using a RECURSIVE function. tip: a. check if the length of n = 1, if true, return n and stop b. else, if the length of n >= 1, do the ff: c. get the min(x) (least rank word in alphabetical order) d. create a new array from n, where the min is removed. The new array is m. e. return the array composed of the min + code(m).The sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). Implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. Needs to written in Python with the use of funtions and input parcersWritten in Dr Racket: Write a recursive function that takes a list of numbers as input and returns a list of the numbers in ascending order.Use the quicksort algorithmUse ( 20 13 74 5 12 9 22 95 22 6 101 72 3 53 33 21 96) as input. To do that, calculate the average value of a sublist before dividing it.(quicksort ‘( 20 13 74 5 12 9 22 95 22 6 101 72 3 53 33 21 96))returns ‘(3 5 6 9 12 13 20 21 22 22 33 53 72 74 95 96 101) Do not use sort, quicksort, set!, or mean.
- Implement the vacuum cleaning agent function in Python/Java for the scenario described below: Consider two-dimensional Boolean array of size m x n (m and n can each be equal to 4) where m is the number of rows, and n is the number of columns. Obtain numerical positive integer values for m and n as inputs from the user. Generate random numbers and scale them down to either a “0” or a “1” according to whether they represent “Clean” or “Dirty”, respectively. After filling the array with 0s or 1s, start at some random array position indicating the initial position of the vacuum cleaner. First check if at that current position, there is the presence of a “Dirt” or not determined by whether 0 or 1 is filled in at that initial position of the vacuum cleaner. If there is a “Dirt”, clean it, and if there is no “Dirt” do a No-operation. After this is done, generate random numbers modulo 4 to obtain random numbers 0, 1, 2, 3 indicating whether to take a left, right, up or down correspondingly. If…C++ What is the code below doing? Find the short code can replace its function (For example: sort, replace, search, ...) int* Algorithm1(int limit){bool* sieve = new bool[limit >> 1];for (int i = 0; i < sizeof(sieve) / sizeof(sieve[0]); i++) sieve[i] = true;for (int p = 3, s = 9; s < limit; p += 2){if (sieve[p >> 1]){for (int q = s; q < limit; q += p << 1)sieve[q >> 1] = false;}s += (p + 1) << 2;}int* primes = new int[sizeof(sieve) / sizeof(sieve[0])];if (limit > 2)primes[0] = 2;for (int i = 1; i < sieve.size(); ++i){if (sieve[i])primes.push_back((i << 1) + 1);}return primes;}two_sum is a Python function that takes in a list of integers (elements) and an integer number (num) and returns True if there exist two values in elements that add up to num, otherwise, function returns False. def two_sum(elements: List[int], num: int): for i in range(len(elements)): for j in range(i + 1): if elements[i] + elements[j] == num: return True return False Study above function and answer below questions: A. What is time complexity of two_sum? B. Is it possible to improve on above algorithm performance (in terms of its asymptotic cost)? If yes, describe your algorithm, be detailed as much as possible.