You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x +98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) 29.5 and y = 59.2, you obtain

You run a regression analysis on a bivariate set of data (n = 10). With the regression equation What is the predicted response value? y = = y = -1.328x +98.376 with a correlation coefficient of r = -0.119. You want to predict what value (on average) for the response variable will be obtained from a value of x = 50 as the explanatory variable. (Report answer accurate to one decimal place.) 29.5 and y = 59.2, you obtain

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter1: Equations And Graphs

Section: Chapter Questions

Problem 10T: Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s...

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Olympic Pole Vault The graph in Figure 7 indicates that in recent years the winning Olympic men’s pole vault height has fallen below the value predicted by the regression line in Example 2. This might have occurred because when the pole vault was a new event there was much room for improvement in vaulters’ performances, whereas now even the best training can produce only incremental advances. Let’s see whether concentrating on more recent results gives a better predictor of future records. (a) Use the data in Table 2 (page 176) to complete the table of winning pole vault heights shown in the margin. (Note that we are using x=0 to correspond to the year 1972, where this restricted data set begins.) (b) Find the regression line for the data in part ‚(a). (c) Plot the data and the regression line on the same axes. Does the regression line seem to provide a good model for the data? (d) What does the regression line predict as the winning pole vault height for the 2012 Olympics? Compare this predicted value to the actual 2012 winning height of 5.97 m, as described on page 177. Has this new regression line provided a better prediction than the line in Example 2?
Question 1. You run a regression analysis on a bivariate set of data (n=39n=39). With ¯x=44.2x¯=44.2 and ¯y=51.3y¯=51.3, you obtain the regression equationy=3.403x−61.618y=3.403x-61.618with a correlation coefficient of r=0.265r=0.265. You want to predict what value (on average) for the response variable will be obtained from a value of 80 as the explanatory variable.What is the predicted response value?y = (Report answer accurate to one decimal place.) Question 2. See the attachment
Question #6 Listed below are altitudes (thousands of feet) and outside air temperatures (°F) recorded during a flight. Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. There is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions. For the prediction interval, use a 95% confidence level with the altitude of 6327 ft (or 6.327 thousand feet). Altitude 4 8 14 24 27 31 32 Temperature 55 37 20 −5 −27 −41 −57 a. Find the explained variation. ______________ (Round to two decimal places as needed.) b. Find the unexplained variation. _______________ (Round to five decimal places as needed.) c. Find the indicated prediction interval. _____________°F < y < ____________ °F (Round to four decimal places as needed.)
Question 17: You run a regression analysis on a bivariate set of data (n=103n=103). With ¯x=24.3x¯=24.3 and ¯y=75.9y¯=75.9, you obtain the regression equationy=0.659x+59.886y=0.659x+59.886with a correlation coefficient of r=0.883r=0.883. You want to predict what value (on average) for the response variable will be obtained from a value of x=90x=90 as the explanatory variable.What is the predicted response value?y = (Report answer accurate to one decimal place.)
Question 15: You run a regression analysis on a bivariate set of data (n=79n=79). You obtain the regression equationy=3.362x−24.355y=3.362x-24.355with a correlation coefficient of r=0.725r=0.725 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 10 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
Question #9 The table below lists weights (carats) and prices (dollars) of randomly selected diamonds. Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. There is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions. For the prediction interval, use a 95% confidence level with a diamond that weighs 0.8 carats. Weight 0.3 0.4 0.5 0.5 1.0 0.7 Price $513 $1175 $1335 $1401 $5659 $2266 a. Find the explained variation. ______________ (Round to the nearest whole number as needed.) b. Find the unexplained variation. _______________ (Round to the nearest whole number as needed.) c. Find the indicated prediction interval. $ _____________ < y < $ ____________ (Round to the nearest whole number as needed.)