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With the aid of a simple diagram, explain the j-notation method of phasor quantities. Four single-phase generators whose e.m.f.s can be represented by: e, = 20 sin @t; e, = 40 sin(@t + t/2); ez = 30 sin(@t – T/6); e̟ = nected in series so that their resultant e.m.f. is given by e = e, + ez + e; + e4. Express each e.m.f. and the resultant in the form a ± jb. Hence find the maximum value of e and its phase angle relative to ej. %3D 10 sin(@t – t/3); are con-

With the aid of a simple diagram, explain the j-notation method of phasor quantities. Four single-phase generators whose e.m.f.s can be represented by: e, = 20 sin @t; e, = 40 sin(@t + t/2); ez = 30 sin(@t – T/6); e̟ = nected in series so that their resultant e.m.f. is given by e = e, + ez + e; + e4. Express each e.m.f. and the resultant in the form a ± jb. Hence find the maximum value of e and its phase angle relative to ej. %3D 10 sin(@t – t/3); are con-

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2. 20 + j0, 0 + j40, 26 – j15, 5 – j8.66, 51 + j16.34; 53.5, 17°46' lead
Transcribed Image Text:2. 20 + j0, 0 + j40, 26 – j15, 5 – j8.66, 51 + j16.34; 53.5, 17°46' lead
2. With the aid of a simple diagram, explain the j-notation method of phasor quantities. Four single-phase generators whose e.m.f.s can be represented by: e, = 20 sin ot; e, = 40 sin(@t + t/2); ez = 30 sin(@t – Tt/6); e4 = 10 sin(@t – t/3); are con- nected in series so that their resultant e.m.f. is given by e = e¡ + e, + e; + e4. Express each e.m.f. and the resultant in the form a ± jb. Hence find the maximum value of e and its phase angle relative to e¡.
Transcribed Image Text:2. With the aid of a simple diagram, explain the j-notation method of phasor quantities. Four single-phase generators whose e.m.f.s can be represented by: e, = 20 sin ot; e, = 40 sin(@t + t/2); ez = 30 sin(@t – Tt/6); e4 = 10 sin(@t – t/3); are con- nected in series so that their resultant e.m.f. is given by e = e¡ + e, + e; + e4. Express each e.m.f. and the resultant in the form a ± jb. Hence find the maximum value of e and its phase angle relative to e¡.
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