Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to use, and implications and recommendations of/from the conclusions. (What is the characteristic of interest? Is it really just the proportion of males and that of females? Be specific.)

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Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to use, and implications and recommendations of/from the conclusions. (What is the characteristic of interest? Is it really just the proportion of males and that of females? Be specific.)

R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: .Table
X-squared = 1.0088, df = 1, p-value = 0.3152
alternative hypothesis: two.sided
95 percent confidence interval:
-0.1286700 0.4964861
sample estimates:
prop 1 prop 2
0.6666667 0.4827586
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: .Table
X-squared = 1.0088, df = 1, p-value = 0.8424
alternative hypothesis: less
95 percent confidence interval:
-1.0000000 0.4528317
sample estimates:
prop 1
prop 2
0.6666667 0.4827586_
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: .Table
= 0.1576
X-squared = 1.0088, df = 1, p-value
alternative hypothesis: greater
95 percent confidence interval:
-0.08501564 1.00000000
sample estimates:
prop 1
prop 2
0.6666667 0.4827586
Transcribed Image Text:R COMMANDER OUTPUT 2-sample test for equality of proportions with continuity correction data: .Table X-squared = 1.0088, df = 1, p-value = 0.3152 alternative hypothesis: two.sided 95 percent confidence interval: -0.1286700 0.4964861 sample estimates: prop 1 prop 2 0.6666667 0.4827586 R COMMANDER OUTPUT 2-sample test for equality of proportions with continuity correction data: .Table X-squared = 1.0088, df = 1, p-value = 0.8424 alternative hypothesis: less 95 percent confidence interval: -1.0000000 0.4528317 sample estimates: prop 1 prop 2 0.6666667 0.4827586_ R COMMANDER OUTPUT 2-sample test for equality of proportions with continuity correction data: .Table = 0.1576 X-squared = 1.0088, df = 1, p-value alternative hypothesis: greater 95 percent confidence interval: -0.08501564 1.00000000 sample estimates: prop 1 prop 2 0.6666667 0.4827586
In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of
females have normal resting pulse rate compared with males. Dr. Castillejo is interested to know whether this
result also applies among gym members. Use the R commander output below to test Dr. Castillejo's claim.
Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to
use, and implications and recommendations of/from the conclusions. Note: The following R commander
output defines the difference to be Female - Male.
Transcribed Image Text:In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of females have normal resting pulse rate compared with males. Dr. Castillejo is interested to know whether this result also applies among gym members. Use the R commander output below to test Dr. Castillejo's claim. Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to use, and implications and recommendations of/from the conclusions. Note: The following R commander output defines the difference to be Female - Male.
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