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- Write a function in c programming language that gets an array of points ( function is defined as : typedef struct{ int x; Int y; } point; ) and sorts the array using qsort().Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)1⁄2 is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation:(1,1) is first because 12+12=2 is the smallest(3,2)…Write a program in Python with a function squareRoot(x, epsilon) that uses bisection search to return a number y that is close enough to the square root of x, so that abs(y**2 - x) < epsilon.Write pseudocode for a function Det-Quicksort(A, p, r) that receives array A[1..n], and indices p and r. The function should sort the subarray A[p..r] recursively (meaning you should call itself). You can also use a function LinearSearch(A, p, r, v) that searches subarray A[p..r] for an element of value v and return its index (in case it exists) in O(r − p) time. (Just to give you something to compare to, the solution has 8 lines.)
- In C programming Mathematically, given a function f, we recursively define fk(n) as follows: if k = 1, f1(n) = f(n). Otherwise, for k > 1, fk(n) = f(fk-1(n)). Assume that there is an existing function f, which takes in a single integer and returns an integer. Write a recursive function fcomp, which takes in both n and k (k > 0), and returns fk(n). int f(int n);int fcomp(int n, int k){Write a function/ program that produces the following: int findDifference(const string a1[], int n1, const string a2[], int n2); Return the position of the first corresponding elements of a1 and a2 that are not equal. n1 is the number of interesting elements in a1, and n2 is the number of interesting elements in a2. If the arrays are equal up to the point where one or both runs out, return the smaller of n1 and n2. Notwithstanding each function's behavior described below, all functions that return an int must return −1 if they are passed any bad arguments (e.g. a negative array size, or a position that would require looking at the contents of an element past the last element we're interested in). Unless otherwise noted, passing 0 to the function as the array size is not itself an error; it merely indicates the function should examine no elements of the array. Here's an example: string cast[5] = { "samwell", "jon", "margaery", "daenerys", "tyrion" }; string roles[4] = { "samwell",…Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] """ def generate_parenthesis_v1(n): defadd_pair(res, s, left, right): ifleft==0andright==0: res.append(s) return ifright>0: add_pair(res, s+")", left, right-1) ifleft>0: add_pair(res, s+"(", left-1, right+1) res= [] add_pair(res, "", n, 0) returnres def generate_parenthesis_v2(n): defadd_pair(res, s, left, right): ifleft==0andright==0: res.append(s) ifleft>0: add_pair(res, s+"(", left-1, right) ifright>0andleft<right: add_pair(res, s+")", left, right-1).
- Write a function in c++ is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4Write a recursive function named decrypt, which takes a string s and a dictionary d where each key in the dictionary is a string word associated with a secret code as its key. This function should return the list of all possible ways (order it returns it in doesn’t matter) in which the string s can be decoded by splitting it into secret codes and separating the corresponding words of the decoded word with spaces. For instance, calling decrypt('turing', {'turing': 'A', 'tur': 'B', 'ing': 'C', 'tu': 'D', 'ring': 'E', 'ri': 'F', 'ng': 'G'}) returns ['A', 'D E', 'D F G', 'B C']. def decrypt(s: str, d: {str: str}) -> [str]:Implement the following functions in the same application in C#: 1. Given a number (integer) N (greater than 1). Implement a Fibonacci sequence of length N. (Function name ComputeFibonacciSequence )ComputeFibonacciSequence receives N.2. Given a list L with n numbers (integers), implement a function that returns whether that list is even prone or not (i.e.: the number of even numbers in the list must be higher than that of the odd numbers.) (Function name ComputeEvenProne) - Return 1 if the list is even prone, return 0 if it is not.ComputeEvenProne receives L.
- Implement the following function, without using any data structure. /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2)Edsgar Dijkstra is known for his work on programming languages. Hecame up with a neat problem that he called the Dutch National Flagproblem: given a list of strings, each of which is either 'red', 'green', or 'blue'(each is repeated several times in the list), rearrange the list so that thestrings are in the order of the Dutch national flag—all the 'red' stringsfirst, then all the 'green' strings, then all the 'blue' strings.Write a function called dutch_flag that takes a list and solves this problem.Write a function that gets an array of points and sorts the array using qsort(). Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)½ is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation: (1,1) is first because 12+12=2 is the smallest (3,2) is next because 32+22 = 13 is the second smallest Both (3,4) and (5,0) have the same sum of squares, 25, but 3<5 so…