Write a method mergeStrings that will return the strings merged, one letter at a time, starting with one. Please note one and two can be of different lengths.
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using Java ---eclipes
When gears merge and work together, one teeth from each one goes in order.
Write a method mergeStrings that will return the strings merged, one letter at a time, starting with one. Please note one and two can be of different lengths. Please look at below examples:
s1 ==> "12345" s2 ==> "abcde" mergeStrings(s1,s2) ==> "1a2b3c4d5e" mergeStrings("wooden", "spoon") ==> "wsopoodoenn" mergeStrings("java", "selenium") ==> "jsaevlaenium"
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- Using Java. When gears merge and work together, one teeth from each one goes in order. Write a method mergeStrings that will return the strings merged, one letter at a time, starting with one. Please note one and two can be of different lengths. Please look at below examples: s1 ==> "12345" s2 ==> "abcde" mergeStrings(s1,s2) ==> "1a2b3c4d5e" mergeStrings("wooden", "spoon") ==> "wsopoodoenn" mergeStrings("java", "selenium") ==> "jsaevlaenium"Write a method that computes the sum of the digitsin an integer. Use the following method header:public static int sumDigits(long n)For example, sumDigits(234) returns 9 (= 2 + 3 + 4). (Hint: Use the % operatorto extract digits and the / operator to remove the extracted digit. For instance,to extract 4 from 234, use 234 % 10 (= 4 ). To remove 4 from 234, use 234 / 10(= 2 3 ). Use a loop to repeatedly extract and remove the digit until all the digitsare extracted. Write a test program that prompts the user to enter an integer thendisplays the sum of all its digits.Java program Write and test a void method called inOrder() that takes three strings and prints them out in the correct alphabetical order. For example the call of inOrder("abc", "mno", "xyz") will print out the values in the order abc -> mno -> xyz. However the call of inOrder("xyz" , "mno", "abc") will also print abc -> mno -> xyz.. Make sure to test your method, with at least 5 different input variations.
- Complete the method below that prints all elements that are in both Set<String> s and Set<String> t. Each matching element should be followed by a space. What can I change to make it work? import java.util.Set;import java.util.Iterator; public class Sets{ public static void printMatches(Set<String> s, Set<String> t) { System.out.print("{ "); while(in.hasNext()){ String next = in.next(); { if((s.contains(next))&& (t.contains(next))){ System.out.print(next+" "); } } System.out.println("}"); }} import java.util.Set;import java.util.TreeSet;import java.util.Arrays; public class SetsTester{ public static void main(String[] args) { Set<String> set1 = new TreeSet<>(Arrays.asList("Bob", "Bill", "Sally")); Set<String> set2 = new TreeSet<>(Arrays.asList("Sam", "Bob", "Frank")); Sets.printMatches(set1, set2);…Write a method to replace all spaces in a string with '%20'. You may assume that the stringhas sufficient space at the end to hold the additional characters, and that you are given the "true"length of the string. (Note: If implementing in Java, please use a character array so that you canperform this operation in place.)EXAMPLEInput: "Mr John Smith ", 13Output: "Mr%20John%20Smith"Provide a different implementation of ChoiceQuestion. Instead of storing the choices in an array list, the addChoice method should add the choice to the question text. For this purpose, an addLine method has been added to the Question class. Use the following files: Question.java /** A question with a text and an answer.*/public class Question{ private String text; private String answer; /** Constructs a question with empty text and empty answer. */ public Question() { text = ""; answer = ""; } /** Sets the answer for this question. @param correctResponse the answer */ public void setAnswer(String correctResponse) { answer = correctResponse; } /** Checks a given response for correctness. @param response the response to check @return true if the response was correct, false otherwise */ public boolean checkAnswer(String response) { return response.equals(answer); } /** Add a line of text to…
- In java, Implement a method that removes all duplicates. Keep the first instance of the element but remove all subsequent duplicate elements.public void removeDuplicates() see the picture for the right output. Given files: Demo6.java public class Demo6 { public static void main(String[] args) { MyLinkedList<String> list = new MyLinkedList<>(); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); for (int x = 0; x < list.size(); x += 1 + x/3) { System.out.println("Removing element at index: " + x); list.remove(x); } System.out.println("Result"); System.out.println(list); System.out.println("Shuffling"); list.shuffle(7777); System.out.println(list); System.out.println("Removing duplicates (keeping first instance)"); list.removeDuplicates(); System.out.println(list); }} TestBench.java import java.util.AbstractList; public class TestBench { public static…How do I write this java program in hashmap? The program should create charts showing the consistency of the two judges. The rows represent the scores given by Dr. Stansifer and the columns represent the scores given by Dr. Shoaff. Suppose the maximum score is 3 the judges give the following scores. Manatee ID Dr. Shoaff's Score Dr. Stansifier's Score 1 0 0 23 0 3 14 0 0 5 3 0 19 2 3 18 1 1 12 3 2 204 1 1 6 0 0 25 3 3 The consistency chart resulting from these scores are: 0 1 2 3 0 3 0 0 1 1 0 2 0 0 2 0 0 0 1 3 1 0 1 1 The "3" in the upper left hand corner indicates that there were 3 manatees that Dr Shoaff and Dr Stansifer gave a 0 score. (namely manatee 1, 14, 6). The 1 in row 0, column 1 indicates there was 1 manatee that Dr. Shoaff scored a 0 while Dr Stansifer scores a 3 (namely manatee 23). Ideally the only non-zero entries in the table would be along the diagonal indicating perfect consistency. Your program should take a group of scores…Write a method sameVowelsStrings that takes three Strings as input. The method returns true if the three Strings contains the same unique vowels, false otherwise. Note that vowels are 'a', 'e', 'i', 'o' and 'u'. For example: • sameVowelsString("apple", "cattle", "accept") returns true. All strings have a and e as their vowels. • sameVowelsStrings("apple", "banana", "assume") returns false. The second string is missing the vowel e.The first and second strings are missing the vowel u • sameVowelsStrings("apple", "orange", "recordable" ) returns false. The first string is missing the vowel o. • sameVowelsStrings("e", "ee", "eee" ) returns true. They all have vowel e. Subject: Java Programming
- How do I write a java program to count the number of times each finger presses one of the keys using hashSet? When playing music on an Eb Alto Saxophone, the fingers press some keys more than others. For simplicity assume that the music is composed of only 1414 different notes. They are: C D E F G A B in one octave and C D E F G A B in a higher octave. We use c,d,e,f,g,a,b,C,D,E,F,G,A,B to represent them. The fingers typically used for each note are: c: finger 22-44, 77-1010 d: finger 22-44, 77-99 e: finger 22-44, 77, 88 f: finger 22-44, 77 g: finger 22-44 a: finger 22, 33 b: finger 22 C: finger 33 D: finger 11-44, 77-99 E: finger 11-44, 77, 88 F: finger 11-44, 77 G: finger 11-44 A: finger 11-33 B: finger 11-22 (Note that every finger is controlling a specific key, different fingers are controlling different keys.) A finger presses a key if it is needed in a note, and if that same finger is not used in the note previously played. Naturally, every key…I'm developing a card game that requires one deck of 52 cards using Java. Based on the code below, it outputs the total point chosen from the sorted suit out of the 5 cards that gives the highest point. I used hashmaps to program this code. Instead, I want the program to perform the same as before but using comparable/comparator instead of hashmaps. import java.util.HashMap; import java.io.*; public class CardPointsList { static HashMap<String,Integer> Code = new HashMap<>(); static HashMap<Character,Integer> Order = new HashMap<>(); static String[][] hand= {{ "c5","s6","sK","dK","dA"},{"s7","s4","dJ","sA","h5"},{"sQ","d3","c9","hK","d5"}}; static int[] scores={0,0,0}; public static void sortHand() { String temp; for (int h=0;h<3;h++) {for (int i=0;i<5;i++) { for (int j=i+1;j<5;j++) { if (hand[h][j].charAt(0) < hand[h][i].charAt(0)) {temp = hand[h][j]; hand[h][j] = hand[h][i];…Write a method to return the reverse order for a list of space separated words. Example: "A sample sentence is required" would return "required is sentence sample A" I have this to start: class Solution: def reverse_words(self, input): # Your code goes here These are the tests: from solution import Solution import unittest class SolutionTests(unittest.TestCase): def test1(self): solution = Solution() self.assertEqual(solution.reverse_words("the quick brown fox"), "fox brown quick the") if __name__ == '__main__': unittest.main() Any help would be appreciated!
