Write a recursive MIPS program that computes this sequence of numbers (0,1,3,9, 35, 169,987, 6769, 53307, 473841, 4691027,...) can be computed with the following recursive function: int funt (int n) { if (n == 0) return 0; else if (n == 1) return 1; else return (n-1) *funt (n-1) + (n-2) *funt (n-2) + 2; } Thus, funt(0) = 0, funt(1) = 1, funt(2) = 3, funt(3)=9, funt(4) = 35, ... funt(10)= 4691027. Be sure you aren't off by 1 in the sequence! Your main code is main () { } cout<<"Please enter n: "; cin>>n; cout<<"The number series of n numbers is: "; for (inti = 0; i <= n; i++) { cout<

Write a recursive MIPS program that computes this sequence of numbers (0,1,3,9, 35, 169,987, 6769, 53307, 473841, 4691027,...) can be computed with the following recursive function: int funt (int n) { if (n == 0) return 0; else if (n == 1) return 1; else return (n-1) funt (n-1) + (n-2) funt (n-2) + 2; } Thus, funt(0) = 0, funt(1) = 1, funt(2) = 3, funt(3)=9, funt(4) = 35, ... funt(10)= 4691027. Be sure you aren't off by 1 in the sequence! Your main code is main () { } cout<<"Please enter n: "; cin>>n; cout<<"The number series of n numbers is: "; for (inti = 0; i <= n; i++) { cout<

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 17PE

See similar textbooks

Similar questions

Write a recursive Fibonacci function that computes the Fibonacci number for input n and prints each value computed in the series at each recursive step in the sequence from 0 to n, all in one line on the console. (In python)
Consider the recursive procedure which computes the nth Fibonacci number is the one below. procedure Fl (n) //a function which returns the nth Fibonacci number.// if n < 2 then return(n) else return (F2(2,n,1,1)) endif end Fl procedure F2(i,n,x,y) if i
Write a program that performs the following functionalities:1. Fibonacci: a recursive function that computes the fibonacci series, which is defined as followsfibonacci (n) = fibonacci(n-2) + fibonacci(n-1)fibonacci(0) = 0fibonacci(1) = 1 So the fibonacci looks like: 0 1 1 2 3 5 8 13 21 34 …. Therefore, fibonacci(4) = 3, fibonacci(5) = 5, fibonacci(7)=13 2. Sum: a recursive function that computes the sum of integers 1, 2, 3, …., n for a given number n. So Sum(6) should return 1 + 2 + 3 + 4 + 5 + 6 , i.e. 21.sum(n) = n + sum(n-1) 3. Largest: a recursive function that computes the largest value for an integer array of positiveand negative values. For example, for the array below, the function largest should return 22,which is the largest value in the array. You can assume there are no more 20 integers in thearray. Think of how to formulate the recurrence relation in this problem yourself. 4. The 4th problem mimics the situation where eagles flying in the sky can be spotted and…
Write a program using a user defined recursive function to implement the following code segment. main() will call the recursive function and print the value of sum.int n, i, sum;n= last_two_digits_of_your_student_id+3;sum=0;for (i=n-3; i<=n; i++){sum=sum+i;}printf(“%d”, sum)
is it correct ? Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13...... Answer: #include <iostream> using namespace std; int getFibonacci(int n) { if (n == 0 || n == 1) return n; else return getFibonacci(n - 1) + getFibonacci(n - 2); } int main() { int n = 7; int result = getFibonacci(n); cout << result; }
Write a recursive function for Euclid's algorithm to find the greatest common divisor (gcd) of two positive integers. gcd is the largest integer that divides evenly into both of them. For example, the gcd(102, 68) = 34. You may recall learning about the greatest common divisor when you learned to reduce fractions. For example, we can simplify 68/102 to 2/3 by dividing both numerator and denominator by 34, their gcd. Finding the gcd of huge numbers is an important problem that arises in many commercial applications. We can efficiently compute the gcd using the following property, which holds for positive integers p and q: If p > q, the gcd of p and q is the same as the gcd of q and p % q.
In C program We want to emulate that, too! Using a recursive function, make it so that we print the number we are currently in on a new line. When we encounter a number n divisible by 5, we print "YEHEY" and jump 7 steps forward. However when we encounter a number divisible by 8, we print "OHNO" and go back 6 steps. If it is divisible by both, we print "LUCKY" and jump 11 steps. Otherwise just move 1 step. Start at n=1 and continue doing this until you reach a number greater than or equal to the number entered by the user. Instructions: In the code editor, you are provided with a main() function that must ask the user for a number and calls the snake_ladder() function. This snake_ladder() function is a recursive function which should perform the functionality explained in the problem description above. This function is declared but is initially empty. Input 1. Stopping number Description Input the number to which the recursive function must stop Constraints The input is a…
In C program We want to emulate that, too! Using a recursive function, make it so that we print the number we are currently in on a new line. When we encounter a number n divisible by 5, we print "YEHEY" and jump 7 steps forward. However when we encounter a number divisible by 8, we print "OHNO" and go back 6 steps. If it is divisible by both, we print "LUCKY" and jump 11 steps. Otherwise just move 1 step. Start at n=1 and continue doing this until you reach a number greater than or equal to the number entered by the user. Instructions: In the code editor, you are provided with a main() function that must ask the user for a number and calls the snake_ladder() function.This snake_ladder() function is a recursive function which should perform the functionality explained in the problem description above.This function is declared but is initially empty.Input 1. Stopping number Description Input the number to which the recursive function must stop Constraints The input is a positive integer…
The first examples of recursion are the mathematical functions factorial and fibonacci. These functions are defined for non-negative integers using the following recursive formulas:factorial(0) = 1factorial(N) = N*factorial(N-1) for N > 0fibonacci(0) = 1fibonacci(1) = 1fibonacci(N) = fibonacci(N-1) + fibonacci(N-2) for N > 1Write recursive functions to compute factorial(N) and fibonacci(N) for a given non-negative integer N, and write a main() routine to test your functions.(In fact, factorial and fibonacci are really not very good examples of recursion, since the most natural way to compute them is to use simple for loops. Furthermore, fibonacci is a particularly bad example, since the natural recursive approach to computing this function is extremely inefficient.)
Recursion can be direct or indirect. It is direct when a function calls itself and it is indirect recursion when a function calls another function that then calls the first function. To illustrate solving a problem using recursion, consider the Fibonacci series: - 1,1,2,3,5,8,13,21,34...The way to solve this problem is to examine the series carefully. The first two numbers are 1. Each subsequent number is the sum of the previous two numbers. Thus, the seventh number is the sum of the sixth and fifth numbers. More generally, the nth number is the sum of n - 2 and n - 1, as long as n > 2.Recursive functions need a stop condition. Something must happen to cause the program to stop recursing, or it will never end. In the Fibonacci series, n < 3 is a stop condition. The algorithm to use is this: 1. Ask the user for a position in the series.2. Call the fib () function with that position, passing in the value the user entered.3. The fib () function examines the argument (n). If n < 3…
Write the pseudocode for a recursive algorithm to compute b3k, where b is a real number and k is a positive integer. Use the fact that b3k+1=(b3k)3.
The Polish mathematician Wacław Sierpiński described the pattern in 1915, but it has appeared in Italian art since the 13th century. Though the Sierpinski triangle looks complex, it can be generated with a short recursive function. Your main task is to write a recursive function sierpinski() that plots a Sierpinski triangle of order n to standard drawing. Think recursively: sierpinski() should draw one filled equilateral triangle (pointed downwards) and then call itself recursively three times (with an appropriate stopping condition). It should draw 1 filled triangle for n = 1; 4 filled triangles for n = 2; and 13 filled triangles for n = 3; and so forth. API specification. When writing your program, exercise modular design by organizing it into four functions, as specified in the following API: public class Sierpinski { // Height of an equilateral triangle whose sides are of the specified length. public static double height(double length) // Draws a filled equilateral…