is it correct ? Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13...... Answer: #include using namespace std; int getFibonacci(int n) {
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is it correct ?
- Write a recursive function that returns the nth number in a fibonacci sequence when n is passed to function. The fibonacci sequence is like 0,1,1,2,3,5,8,13......
Answer:
#include <iostream>
using namespace std;
int getFibonacci(int n) {
if (n == 0 || n == 1)
return n;
else
return getFibonacci(n - 1) + getFibonacci(n - 2);
}
int main() {
int n = 7;
int result = getFibonacci(n);
cout << result;
}
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- Below,enter code to complete implementation of a recursive function sum_all_integers(), which takes an input n and adds all intergers preceding it, up to n: add_all_integers(n):The Polish mathematician Wacław Sierpiński described the pattern in 1915, but it has appeared in Italian art since the 13th century. Though the Sierpinski triangle looks complex, it can be generated with a short recursive function. Your main task is to write a recursive function sierpinski() that plots a Sierpinski triangle of order n to standard drawing. Think recursively: sierpinski() should draw one filled equilateral triangle (pointed downwards) and then call itself recursively three times (with an appropriate stopping condition). It should draw 1 filled triangle for n = 1; 4 filled triangles for n = 2; and 13 filled triangles for n = 3; and so forth. API specification. When writing your program, exercise modular design by organizing it into four functions, as specified in the following API: public class Sierpinski { // Height of an equilateral triangle whose sides are of the specified length. public static double height(double length) // Draws a filled equilateral…The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.
- Consider the recursive procedure which computes the nth Fibonacci number is the one below. procedure Fl (n) //a function which returns the nth Fibonacci number.// if n < 2 then return(n) else return (F2(2,n,1,1)) endif end Fl procedure F2(i,n,x,y) if iAn arithmetic sequence is a sequence of values where successive values have a common difference. For example, 2,5,8,11,... is an arithmetic sequence starting at 2 with a common difference of 3. We call the starting point s and the difference d. Fill in the missing lines below to write a recursive Python function called arithmetic that takes values for s, d, and n, and returns the nth term of the arithmetic sequence. For example, given the main function: def main(): for i in range(1,6): print(arithmetic(2,3,i)) the output will be: 2 5 8 11 14 Note: No marks will be given for a non-recursive solution. Code with missing lines: # Line 1 # Line 2 # Line 3 # Line 4 # Line 5 Matching each line of code below to its proper line number (Line 1 to Line 5), indicated in the partial code above, to solve the problem. Some lines of code will not be used at all; for these you would select option 6 (i.e., Not Used) from the list of options - do not leave these blank. Question 8 options:…: Write a recursive function to multiply two positive integers without usingthe * operator (or / operator). You can use addition, subtraction, and bit shifting, but you shouldminimize the number of those operations.
- c++ Implement a function that recursively calculates the nth number in the Fibonacci sequence of numbers. The Fibonacci sequence starts at 0 and 1. Each number thereafter is the sum of the two preceding numbers. This gives us the following first ten numbers: 0,1,1,3,5,8,13,21,34, .... Input Expected output0 01 17 139 34Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:1) What are the values of low, high, mid, and target variables?Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:3) If the base case(s) are false, which recursive function call will be made?
- Below is a recursive version of binarySearch:int binarySearch(int nums[], int low, int high, int target){ if (low > high) return -1; int mid = (low + high)/2; if (target == nums[mid]) return mid; else if (target < nums[mid]) return binarySearch(nums, low, mid - 1, target); else return binarySearch(nums, mid + 1, high, target);} Code Analysis ()If we change the first line of code in the function to be “if (low >= high) return -1;”, and we have an array defined as “int nums[] = {2, 3, 5, 7, 8, 10};”, answer the questions below if we called this function with “int index = binarySearch(nums, 0, nums.length - 1, 3);”For each iteration of binarySearch:2) Will a base case be true? If so, what value is being returnedWrite a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…Can someone explain how the output of this recursive function is 12? Recursion is confusing to me. def R(n): if n>=5: return 2 return R(n+1) + 2 print(R(0))