Write an R function called fibo(k) to obtain the Fibonacci numbers less than its argument k.
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Write an R function called fibo(k) to obtain the Fibonacci numbers less than its argument k.
Example:
> fibo(20)
[1] 0 1 1 2 3 5 8 13
> fibo(100)
[1] 0 1 1 2 3 5 8 13 21 34 55 89
> fibo(1000)
[1] 0 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987
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- A function k whose domain is the set of positive integers is defined as k(1)=4 and k(n)=k(n-1)-2. Function k was evaluated for several numbers. Select each statement below that is true. A - k(0)=−2 B - k(2)=2 C - k(3)=0 D - k(6)=3 E - k(−1)=−4Using foldl, define a function num2int :: [Int] -> Int -> Int that converts a list of numbers and the number n into an integer of base n. >num2int [3,4,5,6] 10 3456 >num2int [1,1,0,1,0,0,0,1,0,1,0,1,1,0] 2 3456 num2int :: [Int] -> Int -> Int num2int x y = foldl (\acc (a,b) -> ___a___ + b*y^a) 0 (___b___ (\x y ->(x,y)) [0..] (___c___ x)) fill in blank spaces of a , b , and cPython.Write a function GCD(x,y) that returns the greatest common divisorfor x,y.
- Given a number N (>0). Write a c++ function to find a digit whose frequency is maximum.Function Prototype: void maxFrequencyOfNumber(int num,int & digit, int &maxFreq);Examples:Input: N = 1122322 Output: digit: 2 Max Frequency:4Input: N = 1002023 Output: digit: 0 Max Frequency:3Note: For duplicate max frequency display any digit. For Example:N=10022Output: digit: 0 Max Frequency 2 //OROutput: digit: 2 Max Frequency 2Note: Take input and display output in main function.Solve the question without using arrays.Given a number N (>0). Write a c++ function to find a digit whose frequency is maximum.Function Prototype: void maxFrequencyOfNumber(int num,int & digit, int &maxFreq);Examples:Input: N = 1122322 Output: digit: 2 Max Frequency:4Input: N = 1002023 Output: digit: 0 Max Frequency:3Note: For duplicate max frequency display any digit. For Example:N=10022Output: digit: 0 Max Frequency 2 //OROutput: digit: 2 Max Frequency 2Note: Take input and display output in main function.Q. Taylor Series expansion of sine for x is computed as follows: sin x=x - x^3/3! + x^5/5! - x^7/7!+... Let the value of x be 30, hence radian value for 30 degree is 0.52359 sin(0.52359) = 0.52359 - 0.52359^3/3! + 0.52359^5/5! - 0.52359^7/7!+ ... (a)Write a function in c++ that takes value of x in degrees and returns the value of x in radians. (b)Write a function in c++ that calculates and returns the factorial of a number.e.g. 3!=6 (c)Write a function in c++ that calculates and returns power of a number. e.g. 23=8. (d)Use the above three functions to find the taylor expansion of sine for in degrees as given above.(Calculate first 3 terms)
- Write a function in C programming language that gets two ints x and y, and returns the sum of all ints between x and y, including them. int sum_interval(int x, int y); For example: - sum_interval(1, 4)returns 1+2+3+4=10. - sum_interval(10, 3)returns 3+4+5+6+7+8+9+10=52. - sum_interval(2, -1)returns (-1)+0+1+2=2. - sum_interval(-1, -1)returns -1. Note that we may have x>=y or x<=y. You may assume that the sum will be within the range of int.Write a function find_phone_numbers(text, code='357') that uses a regex to find and extract all the Cypriot phone numbers in a given text sequence. A valid Cypriot phone number starts with either 00 or + followed by the country code 357 and afterwards, 8 numeric digits. Examples: >> find_phone_numbers("""dkdkkdldld +35799394903 dkdkfk 0035799802358 fkfkfld.\n dldld;s;sdd dkdk +30690040404 and +3579933040""") ['+35799394903', '0035799802358'] and also Write a function is_zip_code(zipcode) that uses a regex to test if a given string evaluates to a correct zip code. A correct zip code has a length of 6 characters with the 3 first being letters and followed by 3 digits. Examples: is_zip_code('ABC123') -> True is_zip_code('FYA598') -> True is_zip_code('wyz940') -> True is_zip_code('AB123') -> False is_zip_code('ABCD123') -> False is_zip_code('ABC12') -> FalseA = 3 B = 6 C = 9 D= 7 mod10(X) is a function that returns the modulus of X after dividing it to 10. abs(X) is a function that returns the absolute value of X. Examples: mod10(6) = 6, mod10(16)=6, mod10(0) = 0, mod10(15)=5, mod10(41)+12 = 13 abs(4-8) = 4, abs(8-4)=4, abs(2-9) = 7, abs(8-1) = 7, abs(4-4)=0, abs(2-9)+8 = 15 Calculate the following: K1 = mod10(A+B) + 1= ……. K2 = abs(C-D) + 3 = ……. K3 = abs(D-2) + 1 = ……. K4 = mod10(A+B+C+D) + 1 = ……. K1 = mod((A+B), 10) + 1; K2 = abs(C-D) + 3; K3 = abs((D-2)) + 1; K4 = mod((A+B+C+D),10)+1;
- Write a function that makes the base conversion. It takes two integers n and b as input (n >= 0 andb > 1, both in base 10) and expresses n in base b. For example, the decimal expansion of 345 inbase 10 is 345 = 3 × 102 + 4 × 101 + 5 × 100.Sample input: n = 12, b =2. Sample output: 1100Explanation: (12)10 = (1100)2Write a C++ function factorial that takes an integer, n, and returns the value of n factorial (a.k.a., n!): When n is positive, n! = 1 * 2 * 3 * ... * n. For example, 5! = 1 * 2 * 3 * 4 * 5 = 120. When n is zero, n! is defined to be 1. When n is negative, n! is undefined. You may assume that the parameter n will not be negative for this problem.Write a function that takes 4 Inter gets (num1, den1,num2,den2) as parameters which represent the rational numbers num1/den1, num2/den2 and returns the division of these two fractions. A/B ÷ C/D = A/B × D/C = AD/BC • den 1, den2, and num2 can not be zero. • use multiplication_rat function.