Write down the explicit structures of the compounds given below. a) 2-propanamine b) 1-N, N-dimethylaminocyclohexene c) etanoilbenzoat d) N-methyl-o-toluidine e) 3-Benzyl-5-ethylheptanoic acid
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Write down the explicit structures of the compounds given below.
a) 2-propanamine
b) 1-N, N-dimethylaminocyclohexene
c) etanoilbenzoat
d) N-methyl-o-toluidine
e) 3-Benzyl-5-ethylheptanoic acid
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- Give a clear explanation handwritten answer ....give the detailed answer of each moleculePlease don't provide handwritten solution... red arrows must be drawn on the lower set of structures.An unknown acetylenic amino acid obtained from the seed of a tropical fruit has the molecular formula C7H11NO2. On catalytic hydrogenation over platinum, this amino acid yielded homoleucine (an amino acid of known structure shown here) as the only product. What is the structure of the unknown amino acid?
- The compound whose structure is shown here is acetyl acetone. It exists in two forms:the enol form and the keto form The molecule reacts with OH–to form an anion, [CH3COCHCOCH3] (often abbreviatedacac–for acetylacetonate ion). One or the most interesting aspects of this anion is thatone or more of them can react with transition metal cations to give stable, highlycolored compounds (a) Are the keto and enol forms of acetylacetone resonance forms? Explain youranswer.(b) What is the hybridization or each atom (except H) in the enol form? What changesin hybridization occur when it is transformed into the keto form?(c) What are the electron-pair geometry and molecular geometry around each C atomin the keto and enol forms? What changes in geometry occur when the keto formchanges to the enol form?(d) Draw three possible resonance structures for the acac–ion.(e) Is cis-trans isomerism possible in either the enol or the keto form of acetylacetone?(f) Is the enol form of acetylacetone polar?…How to assay expectorant NH4Cl in details pleaseDraw the possible stereoisomers of 2-methylocta-4,6-dien-1-amine. Note that E-, Z- isomers of each stereoisomer are also possible and would not be accounted for by the formula above; draw any E- or Z- isomers.
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