write some code to muliply num3 (dword) by ecx: num3*ecx Write some code to multiply num4 (byte) by edx.
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Assembly language x86
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- What are the hexadecimal values for the following values by using the little endian byte order? Ox 00 AA 00 BB 00 CC O a. 0x00 AA 00 BB 00 CC Ob. OxAA 00 BB 00 CC 00 O c. OxAA BB CC 00 00 00 O d. 0xCC BB AA Oe. 0xCC 00 BB 00 AA 00Given the following memory word 10101010 generate correspond Hamming codeword?I would like to write a program in C++ to perform my algorithm but am having some trouble. Get the first symbol to be hashed Look up ASCII code Strip off lower 6 bits Set the initial result to these six bits. Repeat Get next symbol to be hashed strip off lower six bits Shift result one bit to the left XOR lower 6 bits of result with new symbol bits, replacing lower 6 bits of result Until there are no more symbols Show final result as a hexadecimal value.
- If you read a word from memory with Hamming code and the retrieved word was: 1001110000111. Then the error in the retrieved word is in position? a. 9 b. 7 c. 6 d. 11Write a program to find the number of ones in the binary representation of a number.Convert the following infix expression into its equivalent postfix expression: (i) (a + b) * c (ii) (a + b) * (c + d) (iii) 95 + 36 * + 97 - 1 (iv) 6 + 9 =
- Is the given set of code words has a prefex property{00,10,01,100,101,0010}(a) Find the Hamming distance between the codewords that correspond to datawords 0111 and 1100. (b) Suppose the Hamming distance you found in part (a) is the minimum Hamming distance between all pairs in the codebook. What does this tell us about the number of errors this code can detect?Make code complete from Psedo code.
- Consider the following code which includes a parity check for the third digit: C=(000,011,101,110). You get the third digit by adding the first two and then using the remainder on division by 2. Can this code detect and count single errors? how can this be implemented?Convert the following string from INFIX to PREFIX: (A+B)^(C-D^E) + (F+G)/H* +^+AB-C^DE / +FGH +AB^-C^DE / +FGH AB+CDE^- ^ FG+H/+ AB+CDE^- ^ +FGH/ (AB)+CDE^- ^ (FGH)+/List an application where you can explain the advantage of using the Gray code over the Binary code.