Write the boolean expression from the given circuit y Select one: a. None of these O b. xy + (x+y)(x+yz) C. xyz+X+y+z O d. x+y+z.(x+y)
Q: A D
A: In the given logic circuit: A = X’ B = (AY)’ C = (Y ⊕ Z)’ D = (B + C)’
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- boolean expression: P = not((not(a.b) + c) + a.c) (c) Show that P (the Boolean expression above) is equivalent to the Boolean expression Q = a · b · not(c) and draw the corresponding circuit.Draw the combinational circuit that directly implements the following Boolean expression:F(x, y, z) = x + xy + y′zDesign a circuit to implement the following truth table, where A and B are inputs and Z is the output. Give the Boolean equation that implements the circuit in the space provided. There may be more than one possible correct answer. You only need to list one possible correct answer. Input Output A B Z 0 0 1 0 1 0 1 0 1 1 1 1
- Draw the combinational circuit that directly implements the Boolean expression: F(x, y, z) = xyz + (y′ + z)Draw the combinational circuit that directly implements the Boolean expression:F(x, y, z) = (x(yXORz)) + (xz)′Design a combinational circuit with three inputs x, y, and z, and three outputs, A, B, and C. When the binary input is 0, 1, 2, or 3, the binary output is one greater than the input. For example, if the inputs are 000, the outputs are 001. When the binary input is 4, 5, 6, or 7, the binary output is two less than the input. For example, when inputs are100, the outputs are 010. Show the truth table for the inputs and outputs. please show all steps , dont just explain
- The boolean expression from prob 3: (X+y’+z’)+(X’+y’+Z)+(X’+y’+Z’)Draw the circuit that corresponds to the following Boolean expression: (P ∧ Q) ∨ (∼ P∧ ∼ Q).Design the simplest circuit that has three inputs, a, b, and c, which returns an output value of 1 whenever g and b are complements of each other or b and c are complements of each other, otherwise the output is 0. Realize the circuit using 4input , 3output PAL