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- 1-A bottle of Na2EDTA.2H2O is labeled with an assay of 100.5%, what is this implied?What is the result of heating to 100 ºC?1. Calculate the percent by volume of acetic acid by fermentation. Assumptions: No volume changed during fermentation and conversion efficiency is 85%. Overall chemical reaction facilitated by Acetobacter aceti:C2H5OH + O2 = CH3COOH + H2OGiven: Volume of 6% C2H5OH = 3 LMolar mass of C2H5OH = 46.07 g/molMolar mass of CH3COOH = 60.06 g/molDensity of C2H5OH = 0.789 g/mLDensity of CH3COOH = 1.05 g/mL1) A polyester made from sebacic acid (CAS# 111-20-6) and 1,6-hexanediol (CAS# 629-11-8) has the molecular weight fractionation listed below. Calculate an appropriate average molecular weight for this polyester. Source: Batzer, H., Macromolecular Chemistry and Physics 5
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- outline a separation scheme for isolating pure aspirin. lab video: https://www.youtube.com/watch?v=Y4NMpO1xI8UConsider the calcination of CaCO3 Before calcination, the initial weight of CaCO3 is 1.005g. After calcination, the final weight becomes 1.0 g.Calculate the fraction reacted of CaCO3A wittig reaction experiment: Week 1 -》 preparation of phosphonium salt Materials : triphenylphosphine (5.3g),methyl Bromoacetate 3.36g (2.1ml) , ethanol 30ml . The yield obtained was 8.93g . Calculate the percentage yield Week 2 -》 Formation of the tlide and wittig reaction Materials :Phosphonium salt (5g), napthyl-2- carboxwaldehyde( 2.65g), 20 ml of water and 5 nl of Nahco3. Yield obtained was 0.51g .Calculate the percentage yield Week 3: Solvent free wittig reaction Materials: Benzyltriphenylphosphonium chloride (0.5g ), 4 - Bromoabenzaldehyde (0.24g), Potassium phosphate (tribasi c) 0.275g .The yield obtained was 1.21g. Calculate the percentage yield
- CaCO3(s)<->Ca^2+(aq)+CO3^2-(g). write down Ksp for this reactionwhat is the difference between these two the aldo condensation reaction was preformed Part A NaoH= 2.5g = 0.0625 mol Benzaldehyde= 2.65 g =0.0250 mol Acetone 0.725 g = 0.0125 mol Theoretical yield=0.0125 mol Actual yield= 2.1g Percent yield=71.67% Expected melting point= 110.5-112 degree Celsius Melting point observered= 112 degree Celsius Part B acetophenone 0.5 g, 4.2 mmol Para-methylbenzaldehyde 0.5 g, 4.2 mmol NaOH=0.18g = mol Theroretical yield=0.93g =0.0519 mol Percent yield=76.8% Actual yield= 0.715 g Melting point observered= 93 degree Celsius Expected melting point =93-94.5 degree CelsiusFor acetylacetone, plot your measured %Enol as a function of the dielectric constant of the solvent. [e(CHCl3)= 4.8 , e(acetone)= 20.7, e(MeCN)= 37.5, e(H2O)= 80.1]. measured %Enol [(CHCl3)= 85 , e(acetone)= 77, e(MeCN)= 56] (a)Determine the line of best fit for your 3 data points (in CHCl3, acetone and MeCN). Record the equation of your trend line and its correlation coefficient. Attach your plot (with axes labels) to this report. (b) Using your line of best fit, estimate the %Enol in water
