Write the scalar equation of the plane with normal vector = [1, 2, 1)] and passing through the point (3, 2, 1). O a) 3x+ 2y+z+ 8 = 0 b) x+ 2y +z+ 8 = 0
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Q: The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1,…
A: The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1,…
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- The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1, -1) is: a. 4x - y + 9z = 0 b. 4x - y + 9z + 7 = 0 c. 4x + y + 9z = 0 d. 4x - y - 9z = 0Determine the scalar equation of a plane through the point (3, 0, 4) and having normal vector n= (2, -1, 4).1. Determine the scalar equation of a plane with normal vector n = [3,1,3] that has a y-intercept of 5.
- Give an equation of the plane with a normal vector n = ⟨1, 1, 1⟩ that passes through the point (1, 0, 0).determine the standard and general equation of a plane that contains the point (3,-2,5) and has a normal vector n=<5,2,-3>Find the equation of the plane in xyz-space through the point P=(3,3,2) and perpendicular to the vector n=(−2,1,5).
- Where does the line that passes through the point (1,0,2) in the direction of the vector <2,-1,4> intersect the xy-plane?Find an equation of the plane. the plane through the point (9, 2, 5) and with normal vector 3i + 5j + 5kFind parametric and vector equation for line segment which reach (2, 2.4 , 3.5) point and parallel to the 3i + 2j -k vector a) (1+3t)i + (4+2t)j + (3-t)k b) (2+3t)i + (2.4+2t)j + (3.5-t)k c) (1+3t)i + (2+t)j - (3.5-2t)k d) (2t)i + (1.5-2t)j + (3.5-1t)k