[ ]: # write your implementation here def isPrime(n): checks whether the positive integer n, which is at least 2, is prime or not It takes n: represnts the integer value to be checked It should return [-1 true or false
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- Can you please help update this? //A6Utilities.java import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.security.SecureRandom;import java.util.List;import java.util.TreeMap;import java.util.function.Function;import java.util.stream.Collectors;public class A6Utilities {/*** Returns the corresponding letter grade. Don't modify this method, simply use it when converting single* grades to their equivalent letter grade** @param grade the integer grade to convert* @return the letter grade equivalent to the integer grade*/private static char letterGrade(final int grade) {if (grade < 0) return '?';else if (grade < 60) return 'F';else if (grade < 70) return 'D';else if (grade < 80) return 'C';else if (grade < 90) return 'B';else if (grade <= 100) return 'A';else return '?';}/*** The method uses Java Streams only. Don't use any looping structures, conditional statements are OK (IF, TERNARY, SWITCH)* <p>* Generates a list of secure…The sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). In python, implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. See template code attached.Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. Ridbit begins with an integer n. In one action, he can perform one of the accompanying tasks: partition n by one of its appropriate divisors, or take away 1 from n in case n is more prominent than 1. An appropriate divisor is a divisor of a number, barring itself. For instance, 1, 2, 4, 5, and 10 are appropriate divisors of 20, however 20 itself isn't. What is the base number of moves Ridbit is needed to make to decrease n to 1? Input The principal line contains a solitary integer t (1≤t≤1000) — the number of experiments. The main line of each experiment contains a solitary integer n (1≤n≤109). Output For each experiment, output the base number of moves needed to lessen n to 1.
- How can I build a recursive algorithm that will support Big (0) operation for this particular program below? I think I'm missing something. I'm stuck on the nodes input Write a program called compute in Java that reads a text file, in.txt, that contains a list of positive integers(duplicates are possible, zero is not considered a positive integer) separated by spaces and/or line breaks.After reading the integers, the program must recursively figure out if the list of integers includes twoequal integers. If the list includes two equal integers, the program prints out Yes. Otherwise, the programprints out No. Assume that in.txt contains at least 2 integers. It is important that your program be namedTwo and that the input file is named in.txt.Examples:• If in.txt contains 8,8 the program must print out Yes.• If in.txt contains 5 3 3 4, the program must print out Yes.• If in.txt contains 11 3 5 11, the program must print out Yes.• If in.txt contains 1 2 3 4 5 6 10, the program must…Python help 1) How can the performance complexity of the following algorithm be described? for x in range(numlterations) for y in range(numlterations): تھا for x in range(numlterations): value = value * x print(value) a. quartic b. logarithmic C. quadratic d. cubic 2) The code for the add method for the ArrayBag class is shown below. What is the missing code? def add(self, item): self.items[len(self)] = item <missing code> a. self.items +=1 b. self.size += 1 C. self = self +1 d. self.len = self.items 4)Python Please. An interesting puzzler for chess buffs is the Knight’s Tour problem, originally proposed by the mathematician Euler. Can the knight piece move around an empty chessboard and touch each of the 64 squares once and only once? We study this intriguing problem in depth here. The knight makes only L-shaped moves (two spaces in one direction and one space in a perpendicular direction). Thus, as shown in the figure below, from a square near the middle of an empty chessboard, the knight (labeled K) can make eight different moves (numbered 0 through 7). A: Draw an eight-by-eight chessboard on a sheet of paper, and attempt a Knight’s Tour by hand. Put a 1 in the starting square, a 2 in the second square, a 3 in the third, and so on. Before starting the tour, estimate how far you think you’ll get, remembering that a full tour consists of 64 moves. How far did you get? Was this close to your estimate? B: Now let’s develop a script that will move the knight around a chessboard…
- Answer must be solved Recursively neighbor(n, prev) Takes a positive integer n and a default argument prev and returns the number of digits in n that have the same digit to its left or to its right. Floor division (//) and modulo (%) operators are useful here. Forbidden methods, operators, and libraries: • You are not allowed to convert n to other data type such str() or list() • You are not allowed to use pow, the ** operator, or import any function (such as math.log) • You are not allowed to declare global variables • You are not allowed to use for/while loops in any form Preconditions n: int -> positive integer prev: int -> positive integer sequence of items Returns: int Examples: >>> neighbor(777) 3 >>> neighbor(469704) 0 >>> neighbor(411477) # 411477 4 >>> neighbor(7951452114587444436999) # 7951452114587444436999 9 >>> neighbor(22222222222222233) 17please used this sample code to solve this problem. import java.util.Scanner;import java.util.ArrayList; public class PhotoLineups { // TODO: Write method to create and output all permutations of the list of names. public static void printAllPermutations(ArrayList<String> permList, ArrayList<String> nameList) { } public static void main(String[] args) { Scanner scnr = new Scanner(System.in); ArrayList<String> nameList = new ArrayList<String>(); ArrayList<String> permList = new ArrayList<String>(); String name; // TODO: Read in a list of names; stop when -1 is read. Then call recursive method. }}Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…
- Requirements: Use Java Programming only. Show screenshots of your work. 6. Write method public static int linearSearch(int [] arr, ine key) which returns the largest index such that arr[index] matches the key. If there is match, returns -1. 7. Write method public static double average(int [] arr) which returns the average of all elements in given array arr. Assume that arr has length at least 1. 8. Write method public void crazyPrint(String sentence, int n) which print out the given sentence n times. Assume n is positive integer.Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…can you please convert this python code into java? Python code is as shown below: # recursive function def row_puzzle_rec(row, pos, visited): # if the element at the current position is 0 we have reached our goal if row[pos] == 0: possible = True else: # make a copy of the visited array visited = visited[:] # if the element at the current position has been already visited then it's a loop. # as then its not possible to reach the last element, set possible to False if visited[pos]: possible = False else: # set visitied for the element as True visited[pos] = True possible = False # if its possible to move left then recurse in the left direction if pos - row[pos] > 0 and row_puzzle_rec(row, pos - row[pos], visited): # return immediately if the goal is reached return True # if its possible to move right then recurse in…