Enhanced binary search  BinarySearchDemo.java  package chapter7; import java.util.Scanner; /** This program demonstrates the binary search method in the ArrayTools class. */ public class BinarySearchDemo { public static void main(String[] args) { // The values in the following array are sorted // in ascending order. int numbers[] = {101, 142, 147, 189, 199, 207, 222, 234, 289, 296, 310, 319, 388, 394, 417, 429, 447, 521, 536, 600}; int result, searchValue; String input; // Create the console input objects. Scanner keyboard = new Scanner(System.in); do { // Get a value to search for. System.out.print("Enter a value to search for: "); searchValue = keyboard.nextInt(); // Search for the value result = binarySearch(numbers, searchValue); // Display the results. if (result == -1) System.out.println(searchValue + " was not found."); else { System.out.println(searchValue + " was found at " + "element " + result); } // Consume the remaining newline. keyboard.nextLine(); // Does the user want to search again? System.out.print("Do you want to search again? (Y or N): "); input = keyboard.nextLine(); } while (input.charAt(0) == 'y' || input.charAt(0) == 'Y'); } /** The binarySearch method performs a binary search on an integer array. The array is searched for the number passed to value. If the number is found, its array subscript is returned. Otherwise, -1 is returned indicating the value was not found in the array. @param array The array to search. @param value The value to search for. */ public static int binarySearch(int[] array, int value) { int first; // First array element int last; // Last array element int middle; // Midpoint of search int position; // Position of search value boolean found; // Flag // Set the inital values. first = 0; last = array.length - 1; position = -1; found = false; // Search for the value. while (!found && first <= last) { // Calculate midpoint middle = (first + last) / 2; for (int i=first; i<=last; i++) System.out.print(array[i] + " "); System.out.println(); System.out.println("First = " + first); System.out.println("Last = " + last); System.out.println("Middle = " + middle); // If value is found at midpoint... if (array[middle] == value) { found = true; position = middle; } // else if value is in lower half... else if (array[middle] > value) last = middle - 1; // else if value is in upper half.... else first = middle + 1; } // Return the position of the item, or -1 // if it was not found. return position; } } Modify the binary search algorithm to search in an array that is sorted descendingly, i.e., the first element is the largest, and the last one is the smallest.   The following is the re-ordered array from the BinarySearchDemo. Use this to test your search algorithm. {600, 536, 521, 447, 429, 417, 394, 388, 319, 310, 296, 289, 234, 222, 207, 199, 189, 147, 142, 101};

Enhanced binary search

 BinarySearchDemo.java 

package chapter7; import java.util.Scanner; /** This program demonstrates the binary search method in the ArrayTools class. */ public class BinarySearchDemo { public static void main(String[] args) { // The values in the following array are sorted // in ascending order. int numbers[] = {101, 142, 147, 189, 199, 207, 222, 234, 289, 296, 310, 319, 388, 394, 417, 429, 447, 521, 536, 600}; int result, searchValue; String input; // Create the console input objects. Scanner keyboard = new Scanner(System.in); do { // Get a value to search for. System.out.print("Enter a value to search for: "); searchValue = keyboard.nextInt(); // Search for the value result = binarySearch(numbers, searchValue); // Display the results. if (result == -1) System.out.println(searchValue + " was not found."); else { System.out.println(searchValue + " was found at " + "element " + result); } // Consume the remaining newline. keyboard.nextLine(); // Does the user want to search again? System.out.print("Do you want to search again? (Y or N): "); input = keyboard.nextLine(); } while (input.charAt(0) == 'y' || input.charAt(0) == 'Y'); } /** The binarySearch method performs a binary search on an integer array. The array is searched for the number passed to value. If the number is found, its array subscript is returned. Otherwise, -1 is returned indicating the value was not found in the array. @param array The array to search. @param value The value to search for. */ public static int binarySearch(int[] array, int value) { int first; // First array element int last; // Last array element int middle; // Midpoint of search int position; // Position of search value boolean found; // Flag // Set the inital values. first = 0; last = array.length - 1; position = -1; found = false; // Search for the value. while (!found && first <= last) { // Calculate midpoint middle = (first + last) / 2; for (int i=first; i<=last; i++) System.out.print(array[i] + " "); System.out.println(); System.out.println("First = " + first); System.out.println("Last = " + last); System.out.println("Middle = " + middle); // If value is found at midpoint... if (array[middle] == value) { found = true; position = middle; } // else if value is in lower half... else if (array[middle] > value) last = middle - 1; // else if value is in upper half.... else first = middle + 1; } // Return the position of the item, or -1 // if it was not found. return position; } }

Modify the binary search algorithm to search in an array that is sorted descendingly, i.e., the first element is the largest, and the last one is the smallest.

The following is the re-ordered array from the BinarySearchDemo. Use this to test your search algorithm.

{600, 536, 521, 447, 429, 417, 394, 388, 319, 310, 296, 289, 234, 222, 207, 199, 189, 147, 142, 101};