x = 1.00 2.00 = Check -Vat Figure 1: A velocity versus time graph of an object moving along the x axis. The velocity versus time graph of an object with a mass of m= 2.46 kg, which starts from rest at x = 0.179 m at t = 0, is displayed above. On this graph, UVA = 4.05 m/s. Part 1) What is the location of the object at t = 3.00 s? m Part 2) What is the acceleration of the object at t = 4.00 s? m/s² 3.00 az Part 3) What is the average speed of the object over the 5.00 s time interval shown? Vavg= 4.00 m/s 5.00 t(s)

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: The Laws Of Motion
Section: Chapter Questions
Problem 5.96CP: A time-dependent force, F = (8.00i - 4.00/j), where F is in newtons and t is in seconds, is exerted...
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Question:
x =
1.00
2.00
3.00
Check
Part 2)
What is the acceleration of the object at t = 4.00 s?
m/s²
4.00
-VAT
Figure 1: A velocity versus time graph of an object moving along the x axis.
The velocity versus time graph of an object with a mass of m= 2.46 kg, which starts from rest at x = 0.179 m at t = 0, is displayed above. On this graph, V₁ = 4.05 m/s.
Part 1)
What is the location of the object at t = 3.00 s?
az =
Part 3)
What is the average speed of the object over the 5.00 s time interval shown?
Vavg=
m/s
5.00
t(s)
Transcribed Image Text:Question: x = 1.00 2.00 3.00 Check Part 2) What is the acceleration of the object at t = 4.00 s? m/s² 4.00 -VAT Figure 1: A velocity versus time graph of an object moving along the x axis. The velocity versus time graph of an object with a mass of m= 2.46 kg, which starts from rest at x = 0.179 m at t = 0, is displayed above. On this graph, V₁ = 4.05 m/s. Part 1) What is the location of the object at t = 3.00 s? az = Part 3) What is the average speed of the object over the 5.00 s time interval shown? Vavg= m/s 5.00 t(s)
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