x² – 4 - 4 dx

Q: -7 dx (x – 2)(x2 + 4)

A:

Q: x2 dx 7-5х3

A: Evaluate it.    ∫x27-5x2 dx

Q: dx 5. S- (4x – x2)°/2

A: Note:- Since you have asked multiple question As per our policy, we will solve the first question…

Q: x2 - 16 dx

A:

Q: Зx3 — 4х2 + 3х dx х2 + 1

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Q: Evaluate

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Q: Зx2-7 dy 2х3+5 dx

A:

Q: x-1 (d) S. dx . x5

A: Given

Q: x² - 3x + 2 17. dx x +1

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Q: 6. dx (x2 + 2x + 2)²

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Q: √(x² + 1)(2x³ − 3) dx . -

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Q: dx S- 2 x-4x+5

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Q: x-3 5). S dx

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Q: (w - 3x +3)dw + ( 3w + x + 9)dx=0

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Q: x²+7x+13 2. S dx x+4

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Q: x3 + 2) dx 2.) S

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Q: Зx3—4х2+3х dx х2+1

A: Integration is a process of finding antiderivative of a function. There are basically two types…

Q: x3 dx х2 — 2х + 1

A: The given question is taken from the calculus in which we have to find the integral of the given…

Q: x2 dx - 1

A: See the details solution in below

Q: xe2x (1+ 2x)2 dx : : 1 (a) None a

A: Let I=∫012xe2x1+2x2dx

Q: |x² – 2|dx 1-3

A: Given: ∫-35|x2-2|dx   =∫-35x2-2dx      (using positive measures we omit the modulus signs)Formula:…

Q: 2x + 2 dx x2 +1

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Q: dx 9-3

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Q: (2x+5)dxt 3y dy = o

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Q: (x² + 4)³/2 -dx

A: Given integral is: I=∫x2+432xdx Integrating it: Put:u=x2+4dudx=xx2+4dx=x2+4xdu…

Q: x +1 「マ-x-6 dx. х2 — х —

A: The integral is ∫x+1x2-x-6dx.   Factorize the denominator. x2-x-6=x2-3x+2x-6=xx-3+2x-3=x-3x+2…

Q: |x + 2| dx -4

A:

Q: dx 4. 1- 2cosx

A: The integration of the 1/(1-2cosx).

Q: (3) ((x² – 5x)e*dx

A: To evaluate: I=∫x2-5xexdx

Q: 3 x2 dx 4

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Q: S dx 2 x-6x

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Q: (x + 5) dx V4 - x2

A: This question can be solved using integration by substitution and using the formula of some special…

Q: (x2 – 2x)dx 2х х— 1

A: Given integral ∫x2-2x dxx-1 Here the degree of the numerator expression is greater than the degree…

Q: x² .2 - 81 dx

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Q: dx 1. (x-3)(x-2)

A: Given I=∫1x-3x-2dx To evaluate the integral I:

Q: 1. dx x2+x-6

A: We can find the integral as below

Q: dx 1+ x2/3

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Q: dx 1 (x2 – x + 1) (3x – 2) 2.

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Q: 6- xdy+(2y-x²-1)dx=0

A: As per rule of bartleby we can solve only one question at a time and we can solve only three subpart…

Q: • S X √x²-4 dx

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Q: dx 3). S. x2+4x+5

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Q: x dx 5. S - x2—4х+5

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Q: 2 (x²) + 4 dx =

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Q: 5x 2 Evaluate: ²3x²dz dy dx 2

A: I am going to solve the problem by using some simple calculus to get the required result of the…

Q: (x^2 + 4)dy = (2x-8xy)dx

A: Answer

Q: (x²+x+8)dx x(х2+3х-4)

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Q: S(3V+) dx (x + 3) + C %3D

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Q: 3. 5 (xº - + 2ex) dx 2ех

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Q: dx 3/2 (1+x²)*2

A: ∫1(1+x2)3/2dx Given that:      NOTE: As per our answering guidelines, we can only answer 1 question…

Q: x² 4+x² 2 dx

A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.