Xb A uranium-235 nucleus decays b X101 Chem 101Xapp.101edu.coSubmitQuestion 20 of 42A balloon at 30.0°C has a volume of 222 mL. If the temperature isincreased to 67.1°C and the pressure remains constant, what will thenew volume be, in mL?mL21XС46789х 100+/-07:31 PMеOTYPE here to search11/18/2019LO

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Asked Nov 19, 2019
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b A uranium-235 nucleus decays b X
101 Chem 101
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Question 20 of 42
A balloon at 30.0°C has a volume of 222 mL. If the temperature is
increased to 67.1°C and the pressure remains constant, what will the
new volume be, in mL?
mL
2
1
X
С
4
6
7
8
9
х 100
+/-
0
7:31 PM
е
OTYPE here to search
11/18/2019
LO
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X b A uranium-235 nucleus decays b X 101 Chem 101 X app.101edu.co Submit Question 20 of 42 A balloon at 30.0°C has a volume of 222 mL. If the temperature is increased to 67.1°C and the pressure remains constant, what will the new volume be, in mL? mL 2 1 X С 4 6 7 8 9 х 100 +/- 0 7:31 PM е OTYPE here to search 11/18/2019 LO

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Expert Answer

Step 1

According to the Charles law, the volume of an ideal gas at a constant pressure will be directly proportional to the absolute temperature of the system. Mathematically, it can be shown as follows:

Voc T
V V
Т, т,
V is the initial volume occupied by the ideal gas
V is the final volume occupied by the ideal gas
T, is the initial tempertaure of the system
T, is the final tempertaure of the system
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Voc T V V Т, т, V is the initial volume occupied by the ideal gas V is the final volume occupied by the ideal gas T, is the initial tempertaure of the system T, is the final tempertaure of the system

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Step 2

In the given problem, the initial volume of the balloon is given to be 222 mL.

The pressure is given to be constant till the volume of the gas changes.

The initial temperature of the balloon is given to be 30oC.

The final temperature of the balloon is given to be 67.1oC.

Step 3

The final volume of the balloon ca...

V V
Т, т,
222 mL
V
30°C
67.1°C
222 mLx67.1°C
30°С
496.54 mL
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V V Т, т, 222 mL V 30°C 67.1°C 222 mLx67.1°C 30°С 496.54 mL

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