X(9) + 4Y(9) = 3Z(g)K, = 3.12 x 10 2 bar 2 at a temperature of 287 °C.Calculate the value of Ke.

Given: Kp = 3.12×10-2 bar-2 Temperature = 287 oC = 560 K R = 8.314×10-2 L.bar/K.mol

Answered: X(g) + 4Y(g) = 3Z(g) K, = 3.12 x 10-²…

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X(g) + 4Y(g) = 3Z(g) K, = 3.12 x 10-² bar ² at a temperature of 287 °C. Calculate the value of Ke.

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter16: Spontaneity Of Reaction

Section: Chapter Questions

Problem 85QAP: Which of the following quantities can be taken to be independent of temperature? independent of...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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X(9) + 4Y(9) = 3Z(g)
K, = 3.12 x 10 2 bar 2 at a temperature of 287 °C.
Calculate the value of Ke.

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