The equilibrium constant in terms of pressures for the reduction of tin(IV) oxide to tin at 25 °C is K, = 0.124, corresponding to the reaction SnO2(s) + 2CO(g) = ) Sn(s) + 2CO2(g) If the total pressure of an equilibrium system at 25 °C is 2.61 atm, calculate the partial pressures of CO(g) and CO2(g). PCo = 14.83 atm Pco2 5.22 atm

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Q: The decomposition of a generic diatomic element in its standard state is represented by the equation…

A: Given :  At 2000 K  ∆G° = 4.94 KJ mol-1  At 3000 K  ∆G° = -62.81 KJ mol-1

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A: Solution-  (a),At 2000K ∆G0f =5.51 kL/mol∆G0f = RT In KIn K=∆G0f-RTIn K = 5510J/mol-8.314J/mol K…

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Q: The decomposition of a generic diatomic element in its standard state is represented by the equation…

A: At 2000 K ∆G° = 4.25 kJmol ≈ 4.25×103 Jmol And, At 3000 K ∆G° = -65.74 kJmol ≈ -65.74×103 Jmol

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.