y 1488 268- I 150 1543 1811

Q: Q 20: I R= 300 l nd Ry= 100 1b , then determine the resultant (R) with respect to x'-Y' axes as…

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Q: 180 180 120 仁30

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Q: A are both in the horizontal position shown. - 3.1 m- 3.44 m E 0.93 m 1 02

A: Speed=1.0revolutionTime t=2.6sTo-Find:-aD=..................m/s2

Q: -26-ト-26→ -3b 26 ---x

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Q: Determine the arc length of the space curve r(t)=20sin(t)i + 21 sin(t)j +29 cos(t)k between t=pi/2…

A: given that, rt=20sinti+21sintj+29costk v=drdt v=d(20sinti+21sintj+29costk)dt…

Q: dy 35+メ9

A: The provided differential equation is given as, dydx=3y2+xyx2

Q: y=23 76 M=2 Find a,6, u

A: Given, Z1  = 23 Z2  = 76 m = 2   For d1 = Z1m = 23 * 2 = 46 For d2 = Z2m = 76 * 2 = 152 For a =…

Q: Q 2: Find Ixx and lyy of the Lamina shown in Fig. 1 80 30 50 110 30 120

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Q: why is it 123.7? isnt it in third quadrant so 180+(90-56.3)=213.7

A: Consider the given force with angle as shown below, The angle α is between the force F and the…

Q: 0.2 m B 0.2 m 1.3 m 0.7 m A P Circular

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Q: 18 40 40 72 13

A: orthographic view : theses are the projection view when viewed by a observer from side view , top…

Q: INA 4.1 (A). Determine the second moments of area about the axes XX for the sections shown in Fig.…

A: Now for determine the second moment of area by using the parallel axis theorem Ix-x=INA+Ar2 Now…

Q: f this solid 60 20 20 70 110 i 3.33 60

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Q: For the Vertical bend shown, find the yeaction foree and their direction. D=300 DsZoomm V, =Sm/s Pz…

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Q: Determine uwethe the lines ate patallel given Per pendiculat , meither: a) y- 5x-2 and y=5x +3…

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Q: c. 576.8179in³

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Q: 12 345

A: let ball is coming from top end to bottom as shown in figure.         we know thatpotential energy…

Q: MATHB 25 55"

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Q: 04 Locate the centroid of the shaded area for the figure shown: Shape 1) a.x ay 4*9-36 72 b/3-9/3…

A: Centroid of an area is the point located in the area which is considered to be placed at an average…

Q: 404-70-103=231 isn't it?

A: Given data: Net work is given and total heat supplied is given. The overall efficiency should be…

Q: The bending equation is Mo a) E M E y R (b) y %3D I I R T. c) CO T Ce R J I T (d) %3D JRI 8/- %3D

A: The general equation of bending case is the relationship between bending moment,bending stress and…

Q: Determine the moment ofinertia of the T-section with respect to itscentroidal xo axis. T 100 mm 400…

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Q: Find the exact arc length of the curve over the stated interval. 36xy = yt + 108, from y = 2 to y =…

A: Given 36xy=y4+108interval→y=2 to y=5 The formula used to solve  L=∫y1y21+(dxdy)2×dy y1=2 ; y2=5

Q: ᴛʜᴇ ꜱᴛᴇᴘᴘᴇᴅ ꜱᴛᴇᴇʟ ꜱʜᴀꜰᴛ ᴄᴀʀʀɪᴇꜱ ᴛʜᴇ ᴛᴏʀQᴜᴇ ᴛ. ᴅᴇᴛᴇʀᴍɪɴᴇ ᴛʜᴇ ᴍᴀxɪᴍᴜᴍ ᴀʟʟᴏᴡᴀʙʟᴇ ᴍᴀɢɴɪᴛᴜᴅᴇ ᴏꜰ ᴛ ɪꜰ ᴛʜᴇ…

A: The given values are - θ=3.5° , τ=14 MPa , G=83 GPa

Q: ᴀɴ ᴀᴍᴍᴏɴɪᴀ ᴠᴀᴘᴏʀ ʀᴇꜰʀɪɢᴇʀᴀᴛɪᴏɴ ᴄʏᴄʟᴇ ᴏᴘᴇʀᴀᴛᴇꜱ ᴀᴛ ᴀɴ ᴇᴠᴀᴘᴏʀᴀᴛᴏʀ ᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇ ᴏꜰ -16 ᴏᴄ ᴀɴᴅ ᴀ…

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Q: shown below. Y-axis 8m Х-аxis 4.6m Z-axis 3.8m 4 15 135kn A

A: Given Load = 135 kN To find Moment at point A

Q: 10-129* Determine the second moments Iz and I, for the shaded area shown in Fig. P10-129. x= 4y - y?…

A: Second Moment Ix, Let's take a small section of length x in parallel to the X axis and of width dy…

Q: 14.6240

A: GIVEN :- d= 2 mm L= 45 density: ρ = 1000 Reynold number : Re = 1600 head loss : hL=10.7 m viscocity…

Q: 10-135 For the shaded composite area shown in Fig. P10- 135, determine The second moment of the area…

A: The moment of inertia about the x-axis for each segment can be determined using the parallel axis…

Q: ꜱʜᴇʟʟ ᴛ46 ɪɴᴅᴜꜱᴛʀɪᴀʟ ʟᴜʙᴇ ᴏɪʟ ʜᴀꜱ ᴀ ᴠɪꜱᴄᴏꜱɪᴛʏ ᴏꜰ ᴀʙᴏᴜᴛ 46.5ᴄꜱᴛ. ᴡʜᴀᴛ ɪꜱ ɪᴛꜱ ᴠɪꜱᴄᴏꜱɪᴛʏ ɪɴ ᴛᴇʀᴍꜱ…

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Q: 80 090- Ø40 16 20 R 20- is 3.14 i 18. 13.

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Q: Draw the free body diagram. 80 mg 60 20 650 mm 200 925 mm mm By

A: Solution:   The free body diagram of the inclined beam is shown below:

Q: 10-136* For the shaded composite area shown in Fig. P10- 136, determine The mixed second moment Iy…

A: Given: To find the mixed section moment Ixy for the above section

Q: () m Y 27

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Q: 9.20 Calculate I, for the shaded region, knowing that y = 68.54 mm. Answer: 12.96 x 10° mm* 30 20 80…

A: Given data: The centroid of the given region along the y-axis, y = 68.54 mm. Draw the schematic…

Q: Determike the magnitade ond 14. N direction f the Sou N moment with rapect 1.5 to Point A A 30 Nm

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Q: 31,11+3153,942m=8600215447m^3 Find m

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Q: Determine the shape factor of the cross section.

A: cross section of this image is made of 5 square with size "a" as shown in fig.       We will find…

Q: B 30° 30°

A: Given: Determine the tension developed in each wire.

Q: ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ Qᴜᴀɴᴛɪᴛʏ ᴏꜰ ʜᴇᴀᴛ ᴄᴏɴᴅᴜᴄᴛᴇᴅ ᴘᴇʀ ᴍɪɴᴜᴛᴇ ᴛʜʀᴏᴜɢʜ ᴀ ᴅᴜʀᴀʟᴜᴍɪɴ ᴄɪʀᴄᴜʟᴀʀ ᴅɪꜱᴄ 127 ᴍᴍ…

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Q: 15.Form the Fig (2) The second moment of area I, is then given by: 50mm Imm 120mm 2mm Fig. (2) 2mm…

A: Given Data: Width of the top flange, w=50 mm

Q: 80 Ø40 16 R 20- 13. 18

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Q: Determine the location of the centroid of the area from the x-axis. Omm 30mm 60mm 56.00 mm B) 26.00…

A: It is required to determine location of centroid from X-axis

Q: 30 30° 106 -30 3 2016

A: The moment of the force can be determined by the following relation The moment due to two forces of…

Q: ᴡᴀᴛᴇʀ ꜰʀᴏᴍ ᴀ ʀᴇꜱᴇʀᴠᴏɪʀ ᴀ 10 ᴍ ᴇʟᴇᴠᴀᴛɪᴏɴ ɪꜱ ᴅʀᴀᴡɴ ʙʏ ᴀ ᴍᴏᴛᴏʀ ᴅʀɪᴠᴇɴ ᴘᴜᴍᴘ ᴛᴏ ᴀɴ ᴜᴘᴘᴇʀ ʀᴇꜱᴇʀᴠᴏɪʀ ʙ ᴀᴛ…

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Q: Find the center of the mass the lamina in the first quadvant bordeved by y=x2ey+4 x44

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Q: Q. 3 Determine the coordinates of controid for the plane lamina aN shown in figure. 32

A: Finding areas for each section A1=15×8=120A2=20×5=100A3=45×4=180

Q: 120 mm 3) Determine the location y for the beam having the tapered cross-sectional area shown…

A: ȳ = 135 mm

Q: m2 F(t) = Fo sin ot Fig. P6.8

A: For solution refer below images.