y ==Vx2-8 A) vertices: (-2/2, 0), (2^/2, 0) foci: (-4, 0), (4, 0) C) vertices: (-8, 0), (8, 0) foci: (-2^/2, 0), (2~2, 0) B) vertices: (0, -22), (0, 2^/2) foci: (0, -4), (0, 4) D) vertices: (-8, 0), (8, 0) foci: (-4, 0), (4, 0)

y ==Vx2-8 A) vertices: (-2/2, 0), (2^/2, 0) foci: (-4, 0), (4, 0) C) vertices: (-8, 0), (8, 0) foci: (-2^/2, 0), (2~2, 0) B) vertices: (0, -22), (0, 2^/2) foci: (0, -4), (0, 4) D) vertices: (-8, 0), (8, 0) foci: (-4, 0), (4, 0)

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.3: Lines

Problem 8E

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Question

Find the vertices and foci for the hyperbola

y ==Vx2-8
A) vertices: (-2/2, 0), (2^/2, 0)
foci: (-4, 0), (4, 0)
C) vertices: (-8, 0), (8, 0)
foci: (-2^/2, 0), (2~2, 0)
B) vertices: (0, -22), (0, 2^/2)
foci: (0, -4), (0, 4)
D) vertices: (-8, 0), (8, 0)
foci: (-4, 0), (4, 0)

Expert Solution

Step 1

Standard equation of hyperbola is given by

Step 2

Given

Step 3

Rewrite the equation into the standard form.

Then we have

Here, the hyperbola has properties

Step 4

Then the vertices are given by

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