y x+15 y 2x

Q: y"+y' - 2y = x2

A: Solution :-

Q: Find y" Зх +2 y = 2х- 3

A:

Q: y = 3x-2x²+x-5; y""

A:

Q: 2x+y=6 x=-5y+3

A: Here given that: 2x+y=6 x=-5y+3 we  have to solve the system

Q: y" - 4y' = 0

A: Given: Ordinary equation is  y''-4y'=0

Q: y" - y' - 2y = 0

A: Given the differential equation is y" - y' - 2y = 0 Here the auxiliary equation is m2 - m - 2 = 0

Q: y = ª+2 (x+ 2)

A:

Q: y" +3y'+y=0

A:

Q: y = (1– 2x) ;y" ¡y"

A:

Q: x- y = 4 y | 7. 3x - 3y = -6

A:

Q: y = (x' - 2x2 +3) (7x² – 4x)

A:

Q: y (1, 2) y = 2 x²

A:

Q: x+ y = 2 y = 3 + 6

A: The given relations are x+y=2 and y=3+6, so here we want to find the value of x

Q: X+2+Y=64

A: Given: x+2+y=64

Q: y = -x – 6 - 2х 3D — Зх + 6 4)

A: NOTE: Refresh your page if you can't see any equations. . the first equation is  the second…

Q: x'y%3=

A:

Q: y = 7x2, y = x2 + 3 %3D

A: Follow the procedure given below.

Q: y = (x + 6)2 - 9

A: Definition used-              The horizontal shift of a function - If the graph of function f(x)…

Q: 3y-6(y+z)+y

A: Distribute -6.

Q: V1 – x² y=

A: As per the instructions, we will be answering only one question. For (5), Given,     So,…

Q: y – 3 = (x+1)

A: To plot the points:

Q: y"-2y"-y'+2y= 0

A:

Q: y = x + 6 y = -2x - 3

A:

Q: y′ = e2x + y − 1

A: Given,

Q: ソ=ーx+1 ソ=-5x -3 y

A: NOTE: Refresh your page if you can't see any equations. . to graph the line, we need only two…

Q: x + y = 12 2x-y 9 %3D

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Find y" 3x +4 y = 2x - 3 y" =D

A:

Q: y = |x + 4|

A: Given: - The equation is, y=x+4 Tp sketch: - The graph of the given equation by point plotting

Q: y' = e2x + y – 1

A: Using method of linear differential equation.

Q: y=2(x - 1)2 + 3

A: Given, To graph y=2(x-1)2+3

Q: y=x*(1-x)ª 4-4x 4+4x

A: Use the chain rule of differentiation.

Q: y = x² + 1 y = 2r- 2

A: Here, from the given figure, the area bounded by the given curves are: A=∫-12∫2x-2x2+1dy dx

Q: y +y - 2y = 0

A: Here we have to solve , the given differential equation  y"+y'-2y=0 ...........(1)

Q: y" – y = x²e*

A:

Q: x+y=7 2x-y=8

A:

Q: Y=-2|x+5|+1

A:

Q: Find y'* 2 2 2 + y*

A:

Q: y = x – 12

A:

Q: 3) x=y+x +3x² – 2x

A:

Q: y=5x+4 y=-x-2

A: The equations are given by y = 5x+4                                   ........1 y = -x-2…

Q: (3x')* (Зх (x'y')²

A: (3x3)4x1y42=3×3×3×3×x12x2×y8

Q: + 2t y' - 6y = 0

A:

Q: {: [ x+y = 2 a. 1-3x = y = 5

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: 1. y""-2y" - 15y' = 0

A:

Q: y" + 2y' - y = 0

A: Definition used -         The solution of the linear differential equation -         The…

Q: y = x²(2 - x²)

A:

Vertices Of An Ellipse

In the study of the conic section of the geometry, An ellipse is a plane curve surrounding two focal points, or foci where the set of all locus of points in the plane has their sum of the distances to the two foci is constant. On the ellipse curve, it is the intersection point of the main axis. In an ellipse graph, the center of the axis is the midpoint of the line segment connecting the foci. The major axis is the line section that runs through the ellipse's foci, while the minor axis runs through the middle and is perpendicular to the major axis.. The ellipse has two endpoints on the major axis which are known as the vertices (in plural), vertex in the singular. The equation of the major axis is 2a, the equation of the minor is 2b and the distance between the major axis and minor axis is 2c. The semi-major axis has a length of a and the semi-minor axis has a length of b. The ellipse's vertices are determined by the elliptical orbit's equation and graph.