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y(n) x(n) + 1 sample delay 1.3 -1.2 1 sample delay -0.6 0.5 What difference equation corresponds to the digital network diagram above? (a) y(n) = r(n) – 1.2.r(n- 1) +0.5 r(n- 2)- 1.3 y(n- 1) +0.6 y(n- 2) (b) y(n) = r(n)- 1.2.r(n-1) +0.5 r(n-2) + 1.3 y(n- 1)-0.6 y(n- 2) (c) y(n) = -r(n)+1.2.r(n-1)-0.5 r(n-2) + 1.3 y(n- 1)-0.6 y(n-2) (d) y(n) = -r(n) + 1.2r(n-1)-0.5 r(n-2)- 1.3 y(n-1) +0.6 y(n-2)

y(n) x(n) + 1 sample delay 1.3 -1.2 1 sample delay -0.6 0.5 What difference equation corresponds to the digital network diagram above? (a) y(n) = r(n) – 1.2.r(n- 1) +0.5 r(n- 2)- 1.3 y(n- 1) +0.6 y(n- 2) (b) y(n) = r(n)- 1.2.r(n-1) +0.5 r(n-2) + 1.3 y(n- 1)-0.6 y(n- 2) (c) y(n) = -r(n)+1.2.r(n-1)-0.5 r(n-2) + 1.3 y(n- 1)-0.6 y(n-2) (d) y(n) = -r(n) + 1.2r(n-1)-0.5 r(n-2)- 1.3 y(n-1) +0.6 y(n-2)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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y(n) x(n)- 1 sample delay +) 1.3 -1.2 1 sample delay -0.6 0.5 What difference equation corresponds to the digital network diagram above? (a) y(n) = r(n) - 1.2.r(n 1) +0.5 r(n 2)- 1.3 y(n- 1) +0.6 y(n- 2) (b) y(n) = r(n) 1.2.r(n- 1) +0.5 r(n- 2) + 1.3 y(n- 1)-0.6 y(n- 2) (c) y(n) = -r(n) + 1.2.r(n-1)-0.5 r(n-2) +1.3 y(n-1)-0.6 y(n-2) (d) y(n) =-r(n) +1.2.r(n-1)-0.5 rin-2)- 1.3y(n-1)+0.6 y(n-2)
Transcribed Image Text:y(n) x(n)- 1 sample delay +) 1.3 -1.2 1 sample delay -0.6 0.5 What difference equation corresponds to the digital network diagram above? (a) y(n) = r(n) - 1.2.r(n 1) +0.5 r(n 2)- 1.3 y(n- 1) +0.6 y(n- 2) (b) y(n) = r(n) 1.2.r(n- 1) +0.5 r(n- 2) + 1.3 y(n- 1)-0.6 y(n- 2) (c) y(n) = -r(n) + 1.2.r(n-1)-0.5 r(n-2) +1.3 y(n-1)-0.6 y(n-2) (d) y(n) =-r(n) +1.2.r(n-1)-0.5 rin-2)- 1.3y(n-1)+0.6 y(n-2)
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