You are given a copper calorimeter that is 900 grams and is in equilibrium, has a temperature of 24 degrees Celsius. We are told that our calorimeter also contains water, specifically 300 grams of it. Now an individual takes ice at 0 degrees Celsius, and has a mass of 75 grams, and puts it in the calorimeter, and ensures that he encloses the latter, through the use of a heat insulating shield. a) Please find temperature of the water when equilibrium has been obtained and all our ice was melted (Ice heat of fusion = 333 joules) In simple terms this means that in order to convert 1 gram of ice to water at 0 degrees celicus, we would need 333 joules of heat. b) Resulting from the process of our part a, please find the total entropy change. Hint: Due to the fact that the temperature of the ice doesn't change, during a phase AS = L/T change it can be considered a heat reservoir, meaning that c) Now when equilibrium was obtained and all our ice was melted, please calculate in joules of how much work would need to be supplied to our system (example using stirring rod) to restore all the water to 24 degrees Celsius

Automotive Technology: A Systems Approach (MindTap Course List)
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ISBN:9781133612315
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Need help with the following problem involving calorimetry! 

You are given a copper calorimeter that is 900 grams and is in equilibrium, has a temperature of
24 degrees Celsius. We are told that our calorimeter also contains water, specifically 300 grams
of it.
Now an individual takes ice at o degrees Celsius, and has a mass of 75 grams, and puts it in the
calorimeter, and ensures that he encloses the latter, through the use of a heat insulating shield.
a) Please find temperature of the water when equilibrium has been obtained and all our
ice was melted
(Ice heat of fusion = 333 joules) In simple terms this means that in order to convert 1
gram of ice to water at 0 degrees celicus, we would need 333 joules of heat.
b) Resulting from the process of our part a, please find the total entropy change.
Hint: Due to the fact that the temperature of the ice doesn't change, during a phase
AS = L/T
change it can be considered a heat reservoir, meaning that |
c) Now when equilibrium was obtained and all our ice was melted, please calculate in
joules of how much work would need to be supplied to our system (example using
stirring rod) to restore all the water to 24 degrees Celsius
Transcribed Image Text:You are given a copper calorimeter that is 900 grams and is in equilibrium, has a temperature of 24 degrees Celsius. We are told that our calorimeter also contains water, specifically 300 grams of it. Now an individual takes ice at o degrees Celsius, and has a mass of 75 grams, and puts it in the calorimeter, and ensures that he encloses the latter, through the use of a heat insulating shield. a) Please find temperature of the water when equilibrium has been obtained and all our ice was melted (Ice heat of fusion = 333 joules) In simple terms this means that in order to convert 1 gram of ice to water at 0 degrees celicus, we would need 333 joules of heat. b) Resulting from the process of our part a, please find the total entropy change. Hint: Due to the fact that the temperature of the ice doesn't change, during a phase AS = L/T change it can be considered a heat reservoir, meaning that | c) Now when equilibrium was obtained and all our ice was melted, please calculate in joules of how much work would need to be supplied to our system (example using stirring rod) to restore all the water to 24 degrees Celsius
Expert Solution
Step 1

Solution:

Given Data:

mc=900 gmTi=24oCmw=300 gmmice=75 gm

 

To Find:

(a) Final temperature of the water.

(b) Total entropy change.

(c) Amount of work to be done. 

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