You are given a non-negative number in the form of list elements. For example, the number 123 would be provided as [1, 2, 3]. Add one to the number and return the output in the form of a new list. import java.util.ArrayList; public class AddOneToArrayList{ public static ArrayList solution(ArrayList list){ // ↓↓↓↓ your code goes here ↓↓↓↓ return new ArrayList<>(); } }
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You are given a non-negative number in the form of list elements.
For example, the number 123 would be provided as [1, 2, 3]. Add one
to the number and return the output in the form of a new list.
import java.util.ArrayList;
public class AddOneToArrayList{
public static ArrayList<Integer> solution(ArrayList<Integer> list){
// ↓↓↓↓ your code goes here ↓↓↓↓
return new ArrayList<>();
}
}
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Solved in 2 steps with 3 images
- java In this assignment you will swap a position in an array list with another. swap() gets 3 arguments, an Arraylist, a position, and another position to swap with. Example swap(["one","two","three"],0,2) returns:["three","two","one"] public static ArrayList<String> swap(ArrayList<String> list,int pos1,int pos2) public static void main(String[] args) { Scanner in = new Scanner(System.in); int size = in.nextInt(); int pos1 = in.nextInt(); int pos2 = in.nextInt(); ArrayList<String> list = new ArrayList<>(); for(int i=0; i < size; i++) { list.add(in.next()); } System.out.println(swap(list, pos1, pos2)); } }Using the picture, use Java to design and implement the class PascalTriangle that will generate a Pascal Triangle from a given number of rows. Represent each row in a triangle as a list and the entire triangle as a list of these lists, implement the class ArrayList for these lists.using arrays or Arraylist in java language Write the method named nOdds().* * Given an ArrayList of positive Integers, return a new list * of length "count" containing the first odd numbers from * the original list. The original will contain at least * "count" odd numbers.* * Examples:* nOdds([3, 2, 4, 5, 8], 2) returns [3, 5]* nOdds([3, 2, 4, 5, 8, 9], 3) returns [3, 5, 9]* nOdds([3, 1, 2, 4, 5, 8], 3) returns [3, 1, 5]* * @param list the ArrayList of Integers to search.* @param count the number of odd numbers to copy.* @return the first "count" odd numbers from the list.*/// TODO - Write the nOdds method here. // A utility method for testing@SuppressWarnings("unchecked")public static <T> ArrayList<T> al(T...o){ArrayList<T> result = new ArrayList<T>();for (T s : o) result.add(s);return result;}
- Fix the following method printEvenIndex so that it will print out the Integers at even indices of the passed-in ArrayList list. import java.util.*; public class Test1 { public static void printEvenIndex(ArrayList<Integer> list) { for (int i) { if (i % 2 == 1) { System.out.print(list.get(i) + ", "); } } } public static void main(String[] args) { //instantiate ArrayList and fill with Integers ArrayList<Integer> values = new ArrayList<Integer>(); int[] nums = {1, 5, 7, 9, -2, 3, 2}; for (int i = 0; i < nums.length; i ++) { values.add(nums[i]); } System.out.println("Expected Result:\t 1, 7, -2, 2,"); System.out.print("Your Result:\t\t "); printEvenIndex(values); } }Write Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList import java.util.*;public class test { public static void main(String[] args) { //Set n =25 int n = 25; //ArrayList of Integer type with size,n=25 ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ //Assign -1 to all the objects of the array list,list list.add(-1); } //Add 1001 to the list list.add(1001); //Add 1100 to the list list.add(1100); //Add 1110 to the list list.add(1110); //Reset the number of elements in the list becomes 28 //Use size() method to get the size of the list. n=list.size(); //for loop to print the list for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } }} 1. Write the Java statement to display the size of the resulting ArrayList from above.using arrays or Arraylist in Java language Write the method filterBySize().* * Given an ArrayList of String, return a new list where only * strings of the given length are retained.* * Examples:* filterBySize(["a", "bb", "b", "ccc"], 1) returns ["a", "b"]* filterBySize(["a", "bb", "b", "ccc"], 3) returns ["ccc"]* filterBySize(["a", "bb", "b", "ccc"], 4) returns []* * @param list the list of Strings to process.* @param n the size of words to retain.* @return a new list of words with the indicated size retained.
- The implementation of a queue in an array, as given in this chapter, uses the variable count to determine whether the queue is empty or full. You can also use the variable count to return the number of elements in the queue. On the other hand, class linkedQueueType does not use such a variable to keep track of the number of elements in the queue. Redefine the class linkedQueueType by adding the variable count to keep track of the number of elements in the queue. Modify the definitions of the functions addQueue and deleteQueue as necessary. Add the function queueCount to return the number of elements in the queue. Also, write a program to test various operations of the class you defined.in java language import java.util.ArrayList;import java.util.Arrays; Write the method named mesh.* * Start with two ArrayLists of String, A and B, each with * its elements in alphabetical order and without any duplicates. * Return a new list containing the first N elements from the two * lists. The result list should be in alphabetical order and without * duplicates. A and B will both have a size which is N or more. * Your solution should make a single pass over A and B, taking * advantage of the fact that they are in alphabetical order, * copying elements directly to the new list.* * Remember, to see if one String is "greater than" or "less than" * another, you need to use the compareTo() method, not the < or > * operators. * * Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]* * @param a an ArrayList of String in alphabetical order.*…Write a program in Java using ArrayList to remove duplicates in the array {0,1,4,5,8,0,9,4}.
- Write a Java program to implement the following: Ask the user to enter the names of 3 Books and store them in an ArrayList called Book Remove the second book from the list Add the user to enter a new book name and store to be the first book of the list Ask the user to enter a book name, search for it in list, and print “exist” or “not exist” Print the book name at index 2 Print all list items using loop Print the size of the listimport java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…In java, Implement a method that removes all duplicates. Keep the first instance of the element but remove all subsequent duplicate elements.public void removeDuplicates() see the picture for the right output. Given files: Demo6.java public class Demo6 { public static void main(String[] args) { MyLinkedList<String> list = new MyLinkedList<>(); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); for (int x = 0; x < list.size(); x += 1 + x/3) { System.out.println("Removing element at index: " + x); list.remove(x); } System.out.println("Result"); System.out.println(list); System.out.println("Shuffling"); list.shuffle(7777); System.out.println(list); System.out.println("Removing duplicates (keeping first instance)"); list.removeDuplicates(); System.out.println(list); }} TestBench.java import java.util.AbstractList; public class TestBench { public static…