You compute a 95% confidence interval for the mean of a variable X from a large random sample to be [22.64, 45.68]. Knowing only this, what is the sample mean and standard error of X, respectively m(X) and SE(X)? Om(X)=31.82 SE(X)=4.96 m(X)=17.24, SE(X)=10.12 m(X)=34.16, SE(X)=5.88 Om(X)=26.94, SE(X)=8.72
You compute a 95% confidence interval for the mean of a variable X from a large random sample to be [22.64, 45.68]. Knowing only this, what is the sample mean and standard error of X, respectively m(X) and SE(X)? Om(X)=31.82 SE(X)=4.96 m(X)=17.24, SE(X)=10.12 m(X)=34.16, SE(X)=5.88 Om(X)=26.94, SE(X)=8.72
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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Question
![You compute a 95% confidence interval for the mean of a variable X from a large random sample to
be [22.64, 45.68]. Knowing only this, what is the sample mean and standard error of X, respectively
m(X) and SE(X)?
m(X)=31.82 SE(X)=4.96
m(X)=17.24, SE(X)=10.12
O m(X)=34.16, SE(X)=5.88
O m(X)=26.94, SE(X)=8.72](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6be0e57-1606-402f-9235-4b7a867e4af7%2F383996e5-1287-4ef9-8477-ec98644a3b0c%2Frjuen08_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You compute a 95% confidence interval for the mean of a variable X from a large random sample to
be [22.64, 45.68]. Knowing only this, what is the sample mean and standard error of X, respectively
m(X) and SE(X)?
m(X)=31.82 SE(X)=4.96
m(X)=17.24, SE(X)=10.12
O m(X)=34.16, SE(X)=5.88
O m(X)=26.94, SE(X)=8.72
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