you have 2.2 moles Xe and 2.5 moles F2, but when you carry out the reaction you end up with only 0.25 moles XeF4. What is the percent yield of this experiment? Xe + 2F2 --> XeF4

Q: 2) A chemist student found out that the theorical yield of NH; on the reaction: Mg;N2 + 6 H20 – 2…

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Q: You have 2.2 mol Xe and 3.3 mol Fa, but when you carry out the reaction you end up with only 0.25…

A: 1- First identify the limiting reagent :  According to the chemical reaction equation,  2mol of F2…

Q: Consider the reaction of 94.4 grams of C3H3 and 72.4 grams O2 What is the theoretical yield of CO2…

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Q: 2 C2H4 + 6 02--> 4 CO2 +4 H20 From the above reaction, if 2.0 mol of CO2 are produced, how many of…

A: Given: In the given reaction-                                        2 C2H4  + 6 O2 ----------->…

Q: CHEMWORK Hexamethylenediamine (C6H16N2) is one of the starting materials for the production of…

A: First we find the mole of reactant and then Theortical yield to find percent yield

Q: You have 2.2 mol Xe and 3.0 mol F2 , but when you carry out the reaction you end up with only 0.25…

A: Percent yield is the value of ratio of actual yield by theoretical yield. Actual yield is amount of…

Q: I just need some explanation for part A. Thanks.

A: In part (a) its asking moles of FeC2O4 that should form if we assume that all the Fe(NH4)2(SO4)2…

Q: In the following reaction, if 49.5 g of Fe are used, how many grams of H2 are made? 2Fe (s) + 3H2SO4…

A: Two moles of fe means 112 gram gives three moles of H2 means 6 gram of H2.

Q: Aluminum reacts with bromine, producing aluminum bromide: 2Al(s) + 3Br2(l) --> 2AlBr3(s) In a…

A: The actual yield of aluminum bromide is 50.3 g. Calculation of number of moles of Br2: Mass =…

Q: What is the percent yield if 108 mg SO2 is isolated from the combustion of 82.7 mg of carbon…

A: we will calculate the number of moles CS2 the molar mass of CS2 = 12.01g/mol + 2*32.07 g/mol =…

Q: Hexamethylenediamine (C6H16N2) is one of the starting materials for the production of nylon. It can…

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Q: Carlo's experiment involves preparing oxygen gas from the decomposition of solid potassium chlorate…

A: Theoretical yield :- The maximum amount of the product that can be obtained when the reactants react…

Q: You have 2.2 mol Xe and 3.4 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: The reaction given is  Xe(g) + 2 F₂ (g) → XeF₄ (g) Given : moles of Xe taken = 2.2 mol Moles of F₂…

Q: A chemist carries out this reaction, starting with an excess of MgCl2 and 8.45 g of Na3PO4…

A: To solve this problem we will consider the stoichiometry the given balanced chemical equation . We…

Q: 4Na,Cr2O7 + 3C, H10 + 16H2SO4 4Na2 SO4 + 4Cr2(SO4)3 + 3C, H10O4 + 16H2O Calculate the theoretical…

A: Inorganic chemistry.

Q: You have 2.2 mol Xe and 3.6 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Number of moles of Xe = 2.2 Number of moles of F2 = 3.6 Number of moles of XeF4 = 0.25 The given…

Q: The percent yield for the reaction PCl3 + Cl2  -> PCl5 is 77.5%.  What mass of PCl5 is expected from…

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Q: in this reaction 2VS3+9O2–> 2VO3+6 SO2 if we were to use 25.4 g of VS3 and 25.2 g of O2, and…

A:

Q: 1. If 100.0 molecules of H₂ and 35.0 molecules of O₂ react, how many molecules of H₂O can be…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Iron reacts with oxygen in the following reaction:  4Fe(s) + 3 O2(g) ---> 2Fe2O3(s) if we begin…

A:

Q: Solve the question

A: The reaction is as follows CuSO4  + 4NH3  → Cu(NH3)4SO4 We have to tell the theoretical yield of…

Q: Balance the reaction shown below:   KNO3+Ca3(PO4)2→K3PO4+Ca(NO3)2KNO3+Ca3(PO4)2→K3PO4+Ca(NO3)2…

A: Recall the unbalanced given reaction    KNO3 + Ca3PO42 → K3PO4 + CaNO32 Here,0.355 grams of KNO3 is…

Q: You have 2.2 mol Xe and 3.3 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given : Moles of Xe taken = 2.2 mol Moles of F2 taken = 3.3 mol And moles of XeF4 formed…

Q: N2 + 3H2 ? 2NH3 1.00 mole of N2 was reacted with 3.00 moles of H2 om the reaction above to produce…

A: When any reaction's exact yield gets divided by its theoretical yield and also multiplied by 100…

Q: You have 2.2 mol Xe and 1.5 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given : Moles of Xe taken = 2.2 mol Moles of F2 taken = 1.5 mol And moles of XeF4 formed…

Q: You have 2.2 mol Xe and 4.0 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: The reaction given is  Xe(g) + 2 F₂ (g) → XeF₄ (g)

Q: If only 15.8 grams of sodium chloride were isolated from the above reaction, what is the percent…

A: Given that :  NaCl produced from reaction = 16.48 g  It means theortical yield of NaCl = 16.48g…

Q: You have 2.2 mol Xe and 2.6 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given, Moles of Xe = 2.2 mol Moles of F2 = 2.6 mol Moles of XeF4 produced = 0.25 mol

Q: You have 2.2 mol Xe and 2.0 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given that:                    Moles of Xe = 2.2 mol    Moles of F2 = 2.0 molMoles of XeF4 = 0.25…

Q: CHEMWORK Hexamethylenediamine (C6H16N2) is one of the starting materials for the production of…

A: The given reaction is - - > C6H10O4(l) + 2NH3 (g) + 4H2(g) - - > C6H16N2(l) + 4H2O(l) Here we…

Q: 2S + O2 --> 2SO2 9.75g of SO2 was obtained out of a possible 11.2g of SO2 What is the theoretical…

A: To solve this problem we have to consider the given mass of SO2 in the question .

Q: You have 2.2 mol Xe and 1.9 mol F2, but when you carry out the reaction you end up with only 0.25…

A: Balanced chemical equation: Xe (g) +  2F2 (g)  ----->  XeF4 (g) Theoretical number of moles of…

Q: 1 Zn + 2 HCl → 1 ZNCI, + 1 H, Given 300 grams of zinc, what is the theoretical yield of hydrogen in…

A: The given chemical reaction is: Zn+2HCl→ZnCl2+H2 The given amount of zinc (Zn) is 300 g.

Q: The deep blue compound Cu(NH3)4S0, is made by the reaction of copper(II) sulfate and ammonia. CuSO,…

A: The reaction given is  Hence 1 mole of CuSO4 will produce 1 mole of Cu(NH3)4SO4 theoretically…

Q: The deep blue compound Cu(NH3)4SO4 is made by the reaction of copper(II) sulfate and ammonia. CuSO…

A: Given: Mass of CuSO4 (limiting reagent) = 47.0 g Actual yield of Cu(NH3)4SO4 = 53.4 g Known: Molar…

Q: You have 2.2 mol Xe and 1.9 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: The formula for percent yield is:  Percent Yield = Actual YieldTheoretical Yield*100 Given actual…

Q: You have 2.2 mol Xe and 3.1 mol F₂, but when you carry out the reaction you end up with only 0.25…

A:

Q: 22.N2 + 3H2 = 2NH3 1.00 mole of N2 was reacted with 3.00 moles of H2 in the reaction above to…

A: The percentage yield for a reaction is the percent ratio of the actual yield to the theoretical…

Q: You have 2.2 mol Xe and 2.0 mol F2 but when you carry out the reaction you end up with only 0.25 mol…

A: The limiting reagent in the chemical reaction is fluorine gas. Two moles of fluorine gas form one…

Q: You have 2.2 mol Xe and 3.4 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given,

Q: 2. Fe,O4 + 4CO --> 3Fe + 4CO, 100.0 g CO reacted with excess Fe,O4. If only 141.3 of Fe were…

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Q: The deep blue compound Cu(NH3)4SO, is made by the reaction of copper(II) sulfate and ammonia. CuSO4…

A: The chemical reaction may be written as: CuSO4(aq)+4 NH3(aq)→Cu(NH3)4SO4(aq) molar mass of CuSO4 =…

Q: What is the percent yield

A: Percent yield = (actual yield/theoretical yield) x 100%  Actual yield of XeF4 = 0.25 (given)

Q: Dichlorine monoxide, Cl,0, is sometimes used as a powerful chlorinating agent in research. It can be…

A:

Q: You have 2.2 mol Xe and 3.2 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: Given: For he reaction: Xe(g) + 2 F₂ (g) → XeF₄ (g) 1  mol  2 mol      1 mol Obtained yield=0.25 mol…

Q: The following chemical reaction occurs on the seafloor: 12 FeO(s) + 2 H2O(1) + CO2(g) → 4 Fez04(s) +…

A:

Q: You have 2.2 mol Xe and 3.9 mol F₂, but when you carry out the reaction you end up with only 0.25…

A: The reaction considered is, Xe (g) + 2F2 (g)→XeF4 (g)

Q: Manganese(III) fluoride, MnF3, can be prepared by the following reaction: 2MnI2(s) + 13F2(g) →…

A: Given, the preparation of MnF3 is given by following reaction ; 2MnI2(s) + 13F2(g) → 2MnF3(s) +…

Q: 1 Zn + 2 HCI → 1 ZNCI, + 1 2, Given 300 grams of zinc, what is the theoretical yield of hydrogen in…

A: